The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Answer:
1
Step-by-step explanation:
2x + 1 = -3x + 6
add 3x
5x + 1 = 6
subtract 1
5x=5
Divide by 5
x=1
If this is correct, please mark brainliest!
The answer would be -x^2 + 6x - 3/2
Black 20% 1/5
navy 25% 1/4
Brown 35% 7/20
other 20% 1/5
hope it helps!!
