<span>tropical. mostly wet, with dense lush growth, but some tropical areas can be dry grasslands Warm all year round A long the equator between the tropic of cancer and the tropic of capricorn. dry. DRY! ...mid latitudes. 5 different climate zones here. ...high latitudes. short mild summers and long,cold winters. ...<span>high lands.</span></span>
Answer:
The Caenorhabditis elegans dauer state is a hibernation-like state of diapause that displays a dramatic reduction in spontaneous locomotion.
Explanation:
Mutations affecting the neurotransmitter dopamine, which regulates voluntary movement in many organisms, can stimulate movement in dauers. The movement of quiescent animals is stimulated by conditions that reduce dopamine signaling and also by conditions predicted to increase dopamine signaling.The stimulation of movement by increased dopamine is much more pronounced in quiescent daf-2(−) dauer and dauer-like adult animals.
In C. elegans hermaphrodites, dopamine is produced by eight neurons and signals via at least four dopamine receptors, DOP-1 through DOP-4. In addition, a presynaptic reuptake transporter, DAT-1, removes dopamine from the extracellular space to terminate signaling. In C. elegans, dopamine is best known for mediating the “basal slowing response” in which the animal's movement slows when it encounters food.. Dopamine is thought to be released in response to food and to act on motor neurons to modulate the animal's movement . Animals that cannot produce dopamine fail to slow in response to food and exogenous dopamine slows the movement of animals cultured without food.The response to dopamine in this situation is complex, as the absence of specific dopamine receptors can have either positive or negative effects on movement.
Answer:
Explanation:
Bacterial count in stock- 1.85x10^6 cfu/ml
Dilution methods
Take 100 uL or (0.1ml) from stock and add to 900ul (0.9ml) saline and mixed it- this makes 10^1dilution.
Now take 100ul from 10^1 dilution and add to next 900ul saline this is 10^2 dilution, similarly do upto 10^5 dilution.
Then take 100ul from 10^ 4 and 10^5 dilution seperately and plate on LB agar plate seperetely and count the colonies.
Cfu/ml formula= (No.of colonies x dilution factor)/0.1 ml
So suppose, 18 colonies formed on 10^4 dilution then total no. Of cells in stock will be 18x10^4/ 0.1= 18x10^5 cfu/ml.
If we dilute 10^4 or 10^5 that's leads to colony count of 18-19 colonies on 10^4 dilution while 2 colonies should come on plate of 10^5 dilution.
