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3 years ago

How to round 3.467 to the nearest hundredths

Mathematics

2 answers:

Yakvenalex [24]3 years ago

7 0

Answer:

nearest hundredth would be the second number after the decimal. 4 is not even at the halfway mark so the hundredth would be 6

Step-by-step explanation:

romanna [79]3 years ago

7 0

We're starting with 3.467

The hundredth is the second number on the right of the decimal point

The 3.4 is fine as is

We need to focus on the last 67

7 is over 4, so we know that it rounds up the number before it by one digit

Knowing this, we know that the 6 becomes a 7

Therefore, the final number is 3.47

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Last year, 50 students attended the winter carnival. This year, 60 students attended the carnival. Which statement below correct

SVETLANKA909090 [29]

Answer: 20% increase

Step-by-step explanation:

change/ original number

(60 - 50 / 50) x 100 = 20

20%

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3 years ago

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Solve the equation <br> 2x+1=-1

Olenka [21]

Answer:

2x=-1-1

2x=2

x=2×2

x=4

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3 years ago

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PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

3 0

3 years ago

Can someone help me

Nikolay [14]

Omg this looks hard

4 0

2 years ago

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So here's the question

Lesechka [4]

Yes, is subtraction, to get their "difference".

first off, let's convert the mixed fractions, to "improper", and then subtract.

$\bf \stackrel{red~yarn}{9\frac{1}{5}}-\stackrel{blue~yarn}{3\frac{11}{25}}$

$\bf -------------------------------\\\\
\stackrel{mixed}{9\frac{1}{5}}\implies \cfrac{9\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{46}{5}}
\\\\\\
\stackrel{mixed}{3\frac{11}{25}}\implies \cfrac{3\cdot 25+11}{25}\implies \stackrel{improper}{\cfrac{86}{25}}\\\\
-------------------------------\\\\
\cfrac{46}{5}-\cfrac{86}{25}\impliedby \textit{our LCD is 25}\implies \cfrac{(5\cdot 46)~~-~~(1\cdot 86)}{25}
\\\\\\
\cfrac{230~-~86}{25}\implies \cfrac{144}{25}\implies 5\frac{19}{25}$

4 0

3 years ago