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aleksklad [387]

2 years ago

5

The intensity of light produced by a light source varies

1 answer:

Harrizon [31]2 years ago

3 0

Answer:

45 foot-candles.

Explanation:

I ∝ 1d2⇒I=kd2

where k is a proportionality constant.

We can solve this problem in two ways, either solving for k and subbing back in or by using ratios to eliminate k. In many common inverse square dependences k can be quite a lot of constants and ratios often save on calculation time. We will use both here though.

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Write -0.37 as a quotient of integers to show that it is rational

Zina [86]

Answer:

-37/100

Step-by-step explanation:

Here, we want to write -0.37 as a quotient of integers

What we are saying is that we want to write it as a fraction of two numbers

That would be;

-0.37 = -37/100

4 0

2 years ago

What’s the answer???

Aleonysh [2.5K]

Answer:

the answer is a

you can subsitute or work backwards

6 0

3 years ago

Read 2 more answers

Please solve the following question.

romanna [79]

Can you add the question please.

5 0

2 years ago

M2/n2 is equivalent to _____.

tankabanditka [31]

Answer:

$\frac{m^2}{n^2}$ is equivalent to $m^2 \cdot n^{-2}$

Step-by-step explanation:

Using exponent rules:

$a^{-n}=\frac{1}{a^n}$

Given the expression:

$\frac{m^2}{n^2}$

⇒ $\frac{m^2}{n^2} = m^2 \cdot \frac{1}{n^2}$

Apply the exponent rule, we have;

$m^2 \cdot n^{-2}$

Therefore, the given expression $\frac{m^2}{n^2}$ is equivalent to $m^2 \cdot n^{-2}$

8 0

3 years ago

If we digitized music in stereo using 24 bits per sample and sampling the analog signal 96,000 times per second, this would gene

ryzh [129]

The bit stream generated on <em>kilobyte per second</em> would be 2304 kilobytes per second.

<u>Given the Parameters</u> :

Number of bits per sample = 24 bits

Sampling frequency = 96000 times per second

The bit rate = Sampling frequency × Number of bits per sample

The bit rate = 24 × 96000 = 2,304,000 bits per second

<u>Converting bits to kilobytes</u> ;

<em>1 kilobytes = 1000 bits</em>

(2,304,000 bits per second ÷ 1000) = 2304 kilobytes per second

Therefore, the bit stream generated would be 2304 kbps

Learn more :brainly.com/question/18109354

6 0

2 years ago