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Zigmanuir [339]
2 years ago
9

Mai poured 2.6 liters of water into a partially filled pitcher. The pitcher then contained 10.2 liters

Mathematics
2 answers:
GalinKa [24]2 years ago
4 0

Answer: a. Diagram B

b. x+2.6=10.4

c. x+2.6=10.4

subtract 2.6 from both sides

x=7.8

d. The solution in the equation represents the amount of water that was in the pitcher prior to Mai poring 2.6 Liters of water in. So there were 7.8 Liters of water in a pitcher, Mai poured 2.6 Liters of water into that same pitchers and the total amount of water in the pitcher was 10.4 Liters.

Olegator [25]2 years ago
4 0
It’s A goodluck and keep your head up!
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Please help thank you!
Arte-miy333 [17]

Answer:

  • golf: $10
  • batting: $2.50

Step-by-step explanation:

We can write two equations in the two unknowns using the given relations. Let g and b represent the costs of a round of golf and a turn in the batting cage, respectively.

  5g +4b = 60 . . . . . Sylvester's expense

  3g +6b = 45 . . . . . Lin's expense

Dividing the second equation by 3 gives ...

  g +2b = 15   ⇒   2b = 15 -g

Substituting into the first equation, we have ...

  5g +2(2b) = 60

  5g +2(15 -g) = 60 . . . . . substitute for 2b

  3g = 30 . . . . . . . . . subtract 30, collect terms

  g = 10 . . . . . . . divide by 3

__

  2b = 15 -10 = 5 . . . . use the value of g to find b

  b = 2.5 . . . . . . . . divide by 2

Mini golf costs $10 per round; batting cages cost $2.50 per turn.

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The answer for this question is "y = -5/3 and x = 8/3"
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