Answer:
A Polynomial can be expressed in terms that only have positive integer exponents and the operations of addition, subtraction, and multiplication. In other words, it must be possible to write the expression without division.
Step-by-step explanation:
<em>EXAMPLES :</em>
- <em> x2 + 2x +5 Since all of the variables have integer exponents that are positive this is a polynomial.</em>
- <em>5x +1 Since all of the variables have integer exponents that are positive this is a polynomial.</em>
- <em>(x7 + 2x4 - 5) * 3x Since all of the variables have integer exponents that are positive this is a polynomial.</em>
- <em>5x-2 +1 Not a polynomial because a term has a negative exponent</em>
- <em>3x½ +2 Not a polynomial because a term has a fraction exponent</em>
- <em>(5x +1) ÷ (3x) Not a polynomial because of the division</em>
- <em>(6x2 +3x) ÷ (3x) Is actually a polynomial because it's possible to simplify this to 3x + 1 --which of course satisfies the requirements of a polynomial. (Remember the definition states that the expression 'can' be expressed using addition,subtraction, multiplication. So, if it's possible to simplify an expression into a form that uses only those operations and whose exponents are all positive integers...then you do indeed have a polynomial equation)
</em>
<h3><em>[Polynomial Equation- is simply a polynomial that has been set equal to]</em></h3>
<u><em>Answer:</em></u>
Area of the circle = π square units ≈ 3.14 square units
<u><em>Explanation:</em></u>
To get the area of the circle, we first need to get the length of its radius
<u>1- getting the radius of the circle:</u>
We are given that the circumference of the circle is 6.28 units
Circumference = 2πr
where r is the radius and π has an approximate value of 3.14
6.28 = 2 * 3.14 * r
r = 1 units
<u>2- getting the area of the circle:</u>
Area of circle = πr²
Area of circle = π * (1)² = π square units ≈ 3.14 square units
Hope this helps :)
In a positively skewed distribution, the extreme scores are larger, thus the mean is larger than the median. Since the mean is 122, the only possible median is 118. Therefore, D.
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We are given the points
<span>(0,-4),(1,0),(2,2)
The standard form a quadratic function (in terms of x) is
y = Ax2 + Bx + C
Subsitute the points
-4 = 0 + 0 + C
C = -4
0 = A + B - 4
2 = 4A + 2B - 4
Solve for A and B
A = -1
B = 5
The function is
y = -x2 + 5x - 4</span>
Answer:
hi
Step-by-step explanation:
