3 years ago

The diameter of a circle is two times its radius. Which equation shows another way to represent the area of a circle?

1 answer:

4 0

If the area for a circle is $A= \pi r^{2}$ , you can write it in terms of its diameter like this: $A= \pi ( \frac{1}{2}d) ^{2}$

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Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
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\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

light travels at 3x10 to the power of 8 meters per second. there are 8.64x10 to the power of 4 seconds in 24 hours. how many met

Vaselesa [24]

Distance = velocity * time

= 3 * 10^8 * 8.64 * 10^4

= 2.592 * 10^13 meters (answer)

6 0

4 years ago

A caterpillar moves at a constant speed of 1/2 inches per second. Let x represent the time travel in seconds and y represent the

Anika [276]

Step-by-step explanation:

Expression = 1/2x = y

Easy algebraic expression