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zhuklara [117]
3 years ago
12

Please help with this.

Mathematics
2 answers:
icang [17]3 years ago
5 0

Answer:

g(1)=-72; g(n)=g(n-1)*(1/6)

Step-by-step explanation:

g(1)= -72*(1/6)^(1-1)=-72*(1/6)^0=-72*1=-72

g(2)=-72*(1/6)^(2-1)=-72*(1/6)^1=-72*(1/6)=-12

g(2)=g(1)*(1/6)

g(n)=g(n-1)*(1/6)

Fantom [35]3 years ago
3 0
1/6 because that person said so
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We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

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