7,912.8 inch³ of aluminum is needed to make 70 metal balls.
Step-by-step explanation:
Step 1:
The area of a sphere is calculated by multiplying
with π and the cube of the radius (r³).
In the given problem, the diameter is 6 inches. So the radius of the spheres is 3 inches.
The volume of a sphere,
So if r = 3 inches and π = 3.14,
cubic inches.
So for a single aluminum ball, 113.04 inch³ of aluminum is needed.
Step 2:
If 113.04 inch³ of aluminum is used for 1 ball, then we multiply 70 with this value to determine the aluminum needed for 70 such balls.
The aluminum needed for 70 metal balls
inch³.
So 7,912.8 inch³ of aluminum is needed to make 70 metal balls.
Answer:
(2,16)
Step-by-step explanation:
y=8x-----------(i)
y= 10x-4---------(ii)
Substituting the value of y=8x in equation (ii)
8x=10x-4
8x-10x=-4
-2x= -4
x=2
Now, substituting the value of x= 2 in equation (i)
y=8x=8(2)=16
Solution of the system is (2,16)
50% = 1/2 = .5
180 multiplied by .5 is 90
hope this helps!!
Answer:
ok the raduis is 16 so pie * 16^2=804.25
Step-by-step explanation: