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3 years ago

Nancy's car travels 300 miles on 12 gallons of gas. How many gallons of gas will she need in order to drive 650 miles?

Mathematics

1 answer:

Stells [14]3 years ago

4 0

The answer should be 24 gallons and a half

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Suppose there are 8 runners competing in the 400 meter race. The fastest three runners will win a ribbon. In how many ways can r

yKpoI14uk [10]

Answer:

$^8C_3=336way$

Step-by-step explanation:

From the question we are told that

Number of runners $N=8$

Distance $d=400m$

Generally the top three places can be determined mathematically as

$^8C_3$

$^8C_3=336way$

therefore the top three can be determined in 336ways

6 0

3 years ago

going into the final exam which will count as two tests amelia has test scores of 79, 86, 74, 63, and 94. What score does amelia

stealth61 [152]

Answer:

going into the final exam which will count as two tests amelia has test scores of 79, 86, 74, 63, and 94. What score does amelia need on the final in order to have an average score of 80

she needs a 60

5 0

1 year ago

I posted this 4 times. Please HELP me.<br> At least try to do it.

Ksenya-84 [330]

It’s the top right one. +4 for x then +2 for y. Explanation: Trust me it’s pretty easy. Good luck

5 0

3 years ago

Prove that if the set of vectors {u1, u2, u3} is linearly dependent and u4 is any vector, then the set {u1, u2, u3, u4} is linea

Lesechka [4]

Answer with Step-by-step explanation:

We are given that the set of vectors ${u_1,u_2,u_3}$ is lineraly dependent set .

We have to prove that the set ${u_1,u_2,u_3,u_4}$ is linearly dependent .

Linearly dependent vectors : If the vectors $u_1,u_2.u_3,u_4$

are linearly dependent therefore the linear combination

$a_1u_1+a_2u_2+a_3u_3+a_4u_4=0$

Then ,there exit a scalar which is not equal to zero .

Let $a_1\neq0$ then the vector $u_1$ will be zero and remaining other vectors are not zero.

Proof:

When $u_1,u_2,u_3$ are linearly dependent vectors therefore, linear combination of vectors of given set

$a_1u_1+a_2u_2+a_3u_3=0$

By definition of linearly dependent vector

There exist a scalar which is not equal to zero.

Suppose $a_1\neq 0$ then $u_1=0$

The linear combination of the set ${u_1,u_2,u_3,u_4}$

$a_1u_1+a_2u_2+a_3u_3+a_4u_4=0$

When $a_1\neq0\; and\; u_1=0$

Therefore,the set ${u_1,u_2,u_3,u_4}$ is linearly dependent because it contain a vector which is zero.

Hence, proved .

5 0

3 years ago

At a leather shop 50 jackets were sold in February the shop keeper at the store wants to encourage the sales team to sell more l

Gekata [30.6K]

If 50 jackes have been sold in February and the team will get bonus by selling 30% more jackets in March, then they'll need to sell:

30% * 50 =
= 30/100 * 50 =
= 3/10 * 50 =
= 3 * 5 =
= 15 [more jackets]

So they'll get the bonus after selling 50 + 15 = 65 jackets.

4 0

4 years ago