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viktelen [127]
3 years ago
14

Someone please help!!!​

Mathematics
1 answer:
valina [46]3 years ago
5 0

9514 1404 393

Answer:

  √26

Step-by-step explanation:

The distance formula can help you here.

  \displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(4-(-1))^2+(2-3)^2}=\sqrt{5^2+(-1)^2}=\sqrt{25+1}\\\\d=\sqrt{\boxed{26}}

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The polynomial p(x)=1−2x2−3x3+4x has what order?<br><br> a. 4<br> b. 2<br> c. 3<br> d. 1
VLD [36.1K]

Answer:

3

Step-by-step explanation:

Given the polynomial : p(x)=1−2x2−3x3+4x

Rearranging : p(x) = -3x³ - 2x² + 4x + 1

Looking at the polynomial Given, we can see that it is a univariate polynomial, that is it has only one variable which is x. Thus for polynomials of this sort, the order of the polynomial is the highest exponent occurring in the polynomial equation. Therefore, the order of the polynomial above is 3, because the highest power of the function is 3.

This means that those with 4 as their highest exponent are of order 4 and those with highest exponent as 2 are of order 2.

3 0
3 years ago
I need help please?!!!!
xeze [42]

Answer: It is true.

Step-by-step explanation:

8 x 8=64

6x8=48

64-48=16

4x12=48

16 is in fact less than 48

5 0
3 years ago
Read 2 more answers
Please Help Me with Q4!!
kondaur [170]

Answer:

0,-3

Step-by-step explanation:

It is where the lines intersect!

6 0
3 years ago
Read 2 more answers
Please help asap!!! i dont understand it
pshichka [43]

Answer:

a

Step-by-step explanation:

A perpendicular bisector, intersects a line at its mid point and is perpendicular to it.

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13)

m = \frac{13-1}{9-(-7)} = \frac{12}{9+7} = \frac{12}{16} = \frac{3}{4}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{3}{4} } = - \frac{4}{3} ←  slope of perpendicular bisector

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(\frac{x_{1}+x_{2}  }{2}, \frac{y_{1}+y_{2}  }{2} )

using (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13) , then

midpoint = ( \frac{-7+9}{2}, \frac{1+13}{2} ) = ( \frac{2}{2}, \frac{14}{2} ) = (1, 7 )

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{4}{3} , then

y = - \frac{4}{3} x + c ← is the partial equation

To find c substitute the midpoint (1, 7) into the partial equation

7 = - \frac{4}{3} + c ⇒ c = \frac{21}{3} + \frac{4}{3} = \frac{25}{3}

y = - \frac{4}{3} x + \frac{25}{3} ← equation of perpendicular bisector

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%20%2B%205y%20-%206y%20%2B%20y" id="TexFormula1" title="4 + 5y - 6y + y" alt="4 + 5y - 6y + y
krek1111 [17]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

4+5y-6y+y  Equation/Question

Step 2

4+5y-6y+y  Combine terms

5y-6y+y

Step 3

5y-6y+y=0  Add them

4

Answer

∴4

Hope this helps

7 0
3 years ago
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