Let's write the equation with formula:-
![\boxed{ \sf \: formula : y -y_{1} = m(x - x_{1})}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Csf%20%5C%3A%20formula%20%3A%20y%20-y_%7B1%7D%20%3D%20%20m%28x%20-%20%20x_%7B1%7D%29%7D)
Where,
- x1 is -1 and y1 is 4 and m is 3
![\tt \: y - 4= 3(x - ( - 1))](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%20y%20-%204%3D%203%28x%20-%20%28%20-%201%29%29)
![\tt \: y - 4 = 3(x + 1)](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%20y%20%20-%204%20%3D%203%28x%20%2B%201%29)
![\tt \: y - 4 = 3x + 3](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%20y%20%20-%204%20%3D%203x%20%2B%203)
![\tt \: y = 3x + 3 + 4](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%20y%20%3D%203x%20%2B%203%20%2B%204)
![\tt \: y = 3x + 7](https://tex.z-dn.net/?f=%20%20%5Ctt%20%5C%3A%20y%20%3D%203x%20%2B%207)
<em>Thus, The correct choice is option C!!~</em>
Answer:
<R=137 degrees
Step-by-step explanation:
I hope this helped !!
<span>2x+ y = 3
x = 2y - 1
Make sure there are NO SPACES in your answer. Include a comma in your answer.
It looks like I could substitute the x=2y-1. Into 2x+y=3
2(2y-1)+y=3
4y-2+y=3
5y=5
y=1
x=2(1)-1
x=1
(1,1)
CHECK
2x+y=3
2(1)+(1)=3
2+1=3
3=3
Left hand side=Right hand side
Check other equation
x=2y-1
1=2(1)-1
1=1
Therefore the solution is (1,1). Since the left hand side= right hand side in each equation</span>
Answer:
Describes f(x) = |x|, the graph opens up, the range is greater than 0, vertex is at 0,0, the domain is greater than 0
does not describe f(x) = |x|, is symmetric to the x axis, and is increasing over (0, arrow)
Step-by-step explanation:
punch the equation into desmos, I didn't cuz I know that the equation looks like, but you can visualize with any graphing calculator
Jesos it’s all pixelated I can’t see anything on mi phone br