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Andre45 [30]
2 years ago
10

Find the volume of the prism. 4 in. 8 in. 8 in. ​

Mathematics
2 answers:
Zinaida [17]2 years ago
4 0

Answer:

256 in^3

Step-by-step explanation:

formula is

volume = length × width × height

4 * 8 * 8 =

256

Temka [501]2 years ago
3 0

Answer:

256

Step-by-step explanation:

8×8=64

64×4=256

64

4

256

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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
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Elden [556K]

Answer:

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Step-by-step explanation:

8 0
3 years ago
The area of the figure. Use 3.14 for pie
balu736 [363]

Answer:

54.5 ft^{2}

Step-by-step explanation:

divide it to one rectangle and two different triangles.

Rectangles area: (8+3)*4 = 44ft^{2}

triangle top: 4*3/2 = 6ft^{2}

triangle bottom: 3*3/2= 4.5ft^{2}

sum the all up: 44+6+4.5 = 54.5ft^{2}

don't know how to do it with π though if that's obligatory

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3 years ago
Idek the answer please help
VashaNatasha [74]

Answer:

A.

Step-by-step explanation:

4 0
3 years ago
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The lakers scored a total of 80 points in a basketball game against the bulls. the lakers made a total of 37 two-point and three
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<span>The answer is 2 three-point shots. Since the Lakers made 37 two-point shots, one multiplies 37 by 2 (37 x 2), which equals 74. Then 74 is subtracted from the total 80 to see how many points are left (80 - 74), which equals 6. To determine the number of three-point shots, 6 is divided by 3 (6/3), which equals 2.</span>
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