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2 years ago

2800 cbf = CBM Round to nearest 10th

Mathematics

1 answer:

zhenek [66]2 years ago

8 0

Answer:

79.3 m³

Step-by-step explanation:

2800 ft³ = 2800 ft³ × ((0.3048 m)/(1 ft))³ ≈ 79.3 m³

The conversion factor for feet to meters is 0.3048 m = 1 ft. You need the cube of that to get to cubic meters from cubic feet.

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Consider the enlargement of the rectangle. Use the proportion to find the missing dimension bod the original rectangle. (Sorry t

fgiga [73]

Here's the right way:

$\dfrac{x}{\frac 3 5} = \dfrac{20}{12}$

$x = \dfrac{20}{12} \cdot \dfrac{3}{5} = 1$

Here's the way they want you to do it:

$\dfrac{x}{\frac 3 5} = \dfrac{20}{12}$

$12 x = 20 \times \dfrac{3}{5} = 12 \textrm{ FIRST BOX}$

$x = 12/12 = 1 \textrm{ SECOND BOX}$

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3 years ago

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In a competative exam of 40 questions plus three months is awarded for a correct answer and minus one for every correct answer t

Alex Ar [27]

Answer:

Step-by-step explanation:

n a competitive exam of 40 questions, +3 is awarded for a correct answer and -1 for every wrong answer. Find the total score if a student had 11 wrong answers in his attempt of all questions.

Answers gotten wrong = 11

answers gotten right = 40 - 11 = 29

total score = (point for correct answer x number of correct answer) + (point for wrong answer x number of wrong answer)

(+3 x 29) + (-1 x 11) = 76

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2 years ago

BIVA

sladkih [1.3K]

Answer:

OPEN PHONE

Step-by-step explanation:

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2 years ago

Pick the digit in the one billion place 263,136,816,799

Sophie [7]

Answer: 3

3,000,000,000

Step-by-step explanation:

Billions have 9 zeros

5 0

1 year ago

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The probability of winning a certain lottery is 1/77076 for people who play 908 times find the mean number of wins

Alex73 [517]

The mean is 0.0118 approximately. So option C is correct

<h3><u>Solution:</u></h3>

Given that , The probability of winning a certain lottery is $\frac{1}{77076}$ for people who play 908 times

We have to find the mean number of wins

$\text { The probability of winning a lottery }=\frac{1}{77076}$

Assume that a procedure yields a binomial distribution with a trial repeated n times.

Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.

$n=908, \text { probability } \mathrm{p}=\frac{1}{77076}$

$\text { Then, binomial mean }=n \times p$

$\begin{array}{l}{\mu=908 \times \frac{1}{77076}} \\\\ {\mu=\frac{908}{77076}} \\\\ {\mu=0.01178}\end{array}$

Hence, the mean is 0.0118 approximately. So option C is correct.

4 0

3 years ago