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3 years ago

Convert to decimal expression 0.2777... To a fraction

1 answer:

5 0

Formula is

d = d(10^k+p - 10^k) / 10^k+p - 10^k

where d = the decimal;
k = number of the non repeating decimal digits; which in this case is one
p = repeating decimal digits which in this case is one

Final Answer for this question after simplifying is 5/18

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The diagonals of kite KITE intersect at point P. If m A. 34°<br> B. 46°<br> C. 68°<br> D. 92°

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Read 2 more answers

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

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3 years ago

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GuDViN [60]

Answer:

The diameter of Circle P is the same length as the radius of Circle Q.

Step-by-step explanation:

The radius of Circle Q is half of 52cm. So you would divide 52 by 2 and get 26cm as the radius of Circle Q. Therefore, the length of the diameter of Circle P is the same length as the radius of Circle Q.

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3 years ago