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Vikki [24]
3 years ago
12

Place pi squared, 10, and square root of 70 in least to greatest

Mathematics
1 answer:
Nutka1998 [239]3 years ago
3 0

Answer:

squaare root of 70<pi squared<10

Step-by-step explanation:

Talking about square root of 70, you can take the answer by approximation. u know square of eight is sixty four and square of nine is eighty one. so 70's square root shluld be between eight and nine. And as the value of pi is 3.14... when square of pi is considerd it should be >9 but <10 as pi>3. So 10 become te greatest

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You roll a 6-sided die.
Lerok [7]

Answer:

\huge\boxed{\text{P(not factor of 35) = } \frac{2}{3}}

Step-by-step explanation:

We can use basic probability to find the probability that this roll is not a factor of 35.

First off, we know that with a six sided die there are 6 possible things we can roll.

1, 2, 3, 4, 5, or 6

Now, what are the factors of 35? The factors of 35 will be any whole number that can be multiplied by another whole number to get 35.

  • We know 1 \cdot 35 = 35, so two factors are 1 and 35.
  • We know 5 \cdot 7 = 35, so two factors are 5 and 7.

Therefore, the factors of 35 are 1, 5, 7, 35.

Both 5 and 7 are inside the range of 1-6. So the probability of rolling a side that's a factor of 35 will be  \frac{2}{6} = \frac{1}{3} since there are two factors and 6 possible options.

This means, logically, there is a  \frac{4}{6} = \frac{2}{3}  chance of not rolling a factor of 35.

Hope this helped!

5 0
3 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
A coin purse contains d dimes and q quarters.There are 20 coins in the purse and the total value of the coins is $4.25.which sys
mel-nik [20]
25q + 10d = 425
q + d = 20

First thing's first, picture 4 quarters. Do you know how much these 4 quarters are worth? Obviously, you'd answer one dollar, but take the time to think about how exactly you came up with this answer.

"Well, it's simple," you might think, "Multiply 0.25 by 4."

Similar to this train of thought, the first equation is formulated by doing exactly that. 'q' represents an unknown number of quarters, and 'd' an unknown number of dimes. We use 25q and 10d, because, well, we're multiplying their value by the number of coins. They're equivalent to 425 because the 20 unknown coins make $4.25 (I converted it to cents to get rid of the pesky decimals, but if you want to keep it as dollars that works too).

Because the equation states that there are 20 coins in total, we know that we can make the equation 'q + d = 20' since there are 20 quarters and dimes in total.

Let me know if you need any further explanation :)
-T.B.
3 0
3 years ago
Read 2 more answers
Chad is getting balloons for his grandmothers birthday party. He wants each balloon string to be 6 feet long. At The party store
finlep [7]

Answer: 258 yards

Step-by-step explanation:

Since Chad wants each balloon string to be 6 feet long, and Chad wants to get 43 balloons, the number of yards of string that he will need will be calculated by multiplying 43 by 6. This will be:

= 43 × 6

= 258 yards of string

8 0
3 years ago
Ik it’s pretty easy but u knowh am not really sure if am right or not
gladu [14]

2,6,18

r = 6/2 = 3

18 *3 = 54

54*3 = 162

162*3=486

Answer: 54,162,486

8 0
3 years ago
Read 2 more answers
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