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Taya2010 [7]
3 years ago
10

Consider the function g(x) = -3x - 4 if the domain value is selected from the set {-8, -2, 0, 3}, which of the following is a co

rresponding range value?
A. 18
B. -10
C. -13
D. -5
Mathematics
2 answers:
Marina86 [1]3 years ago
7 0

Answer:

C. -13

Step-by-step explanation:

Solve for g(x) by replacing x with each domain value in the set. Solving for g(x) will give you these numbers:

{20, 2, -4, -13}

-13 is the only value that appears in the range set and in the multiple choice solutions. Therefore, the answer is C. -13

marissa [1.9K]3 years ago
6 0
C -13

Bc I took the text and got it right
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Raymond baked 15 clay jars each day for 5 days. At the end of the 5 days he noticed that 6 jars came out of the oven with defect
uysha [10]

Answer: C.2:25

Step-by-step explanation:

5 0
3 years ago
Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12
Afina-wow [57]
Hey there, hope I can help!

\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}\cdot \frac{d}{e}=\frac{a\:\cdot \:b\:\cdot \:d}{c\:\cdot \:e} \ \textgreater \  \frac{1\cdot \:1\cdot \:dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \  \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}

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5 0
3 years ago
Round the following percentages to one decimal place.0.698%53.123%0.075%34.337%3.876%
balandron [24]

To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}

4 0
1 year ago
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strojnjashka [21]

Answer:

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Step-x^2by-step explanation:

8 0
3 years ago
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