When the difference between one and two numbers is two, the two numbers are -10 and -12.
Given that,
The difference between one and two numbers is two. Twelve more than six times the second is four times the first.
We have to find the number.
We know that,
The system of equation we get
x=y-2 ----->equation(1)
4x=12+6y ----->equation(2)
Substitute for x in the equation(2)
4(y-2)=12+6y
4y-8=12+6y
4y-6y=12+8
-2y=20
y=-10
Substitute y=-10 in equation(1)
x=-10-2
x=-12
Therefore, The two numbers area -10 and -12 when the difference between one and two numbers is two.
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Problem 5
Apply the Law of Sines
s/sin(S) = r/sin(R)
s/sin(78) = 10/sin(48)
s = sin(78)*10/sin(48)
s = 13.162274
<h3>Answer: 13.162274 approximately</h3>
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Problem 6
Use the Law of Sines here as well.
x/sin(X) = y/sin(Y)
x/sin(53) = 6/sin(22)
x = sin(53)*6/sin(22)
x = 12.791588
<h3>Answer: 12.791588 approximately</h3>
Answer:
9 + 10 = 21
Step-by-step explanation:
9 + 10 = 21
Factor out 9 and 10
9 = 3 · 3 10 = 2 · 5
Next multiply 3 by 2
3 × 2 = 6
Then multiply 3 by 5
3 · 5 = 15
Finally add the products
15 + 6 = 21
