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ivolga24 [154]
3 years ago
6

-4x 25 = 13 solve for x

Mathematics
1 answer:
sammy [17]3 years ago
3 0
- 4x + 25 = 13
4x = 12
x = 3
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How to do this question plz ​
sergeinik [125]

Answer:

The answer is yes.

Step-by-step explanation:

All you have to do is substitute the y, which is 5, and the x, which is 2, into the equation. When you solve it the answer in the end will be 5=5, which means that point (2,5) does line on that line.

3 0
4 years ago
If the Alpha company is 79% staffed and the Beta company is only 62% staffed, what is the relative change of staffing from the A
sweet [91]

Answer:

27.41%

Step-by-step explanation:

Data provided in the question

The staffed of Alpha company = 79%

The staffed of Beta company = 62%

Based on the above information, the relative change of staffing from Alpha to beta company is

As we know that

\bold {\ Relative \ change = \frac{\alpha- \beta }{\beta }}

= \frac{(79 -62)}{62} \% \\\\= \frac{17}{62} \times 100\\\\=0.2741 \times 100\\\\=27.41\ \%

By applying the above formula we can get the relative change and the same is to be applied so that the correct percentage could come

5 0
3 years ago
PLZ SHOW WORK 250 POINTS<br><br> how do you do 1/4 x 750,000
Luba_88 [7]

Answer:

you can do 750000 x 0.25

the answer is 187500

8 0
2 years ago
Read 2 more answers
Someone help me with this table !!!!!!!
Artemon [7]

Answer:  The image of the completed table is shown below

In the completed table, we have the following values (left to right)

  • Row One: 30, 10, 40
  • Row Two: 15, 45, 60
  • Row Three: 45, 55, 100

==============================================

Explanation:

We're told that "40 people responded that they use mouthwash". That means we'll write "40" at the very end of the "use mouthwash" row. This represents the total number of people who use mouthwash, since we're underneath the "total" in that far right column.

Then we're further told that "Of the people who use mouthwash, 30 people use floss", so we'll write "30" in the first row, first column blank space. These are the people who both floss and use mouthwash. Because earlier we know 40 people use mouthwash overall, this leaves 40-30 = 10 people who use mouthwash, but they don't floss.

To summarize so far: In row 1, we have the following values from left to right: 30, 10, 40

The first two items of this row must add to the last item.

---------------------

Now onto row 2

Since 40 people use mouthwash, and 100 people were surveyed, this means that 100-40 = 60 people do not use mouthwash.  The value 60 goes at the very end of row 2. This represents another total.

Like earlier, the first two items must add to the last. So 40+60 = 100.

Now turn to the fact that "45 people responded that they don't floss and don't use mouthwash". This tells us that "45" will be in the "no mouthwash" row and "don't floss" column.

We have 60 people who don't use mouthwash, and 45 of those people also don't floss. Therefore, 60-45 = 15 people do floss but they don't use mouthwash. We'll write "15" in the second row, first column.

Along row 2, we have the following values: 15, 45, 60

----------------------

Row 3

For each column, add up the first two items to get the third one. This will lead to the totals along this bottom row.

  • Floss: 30+15 = 45
  • Don't Floss: 10+45 = 55 .... note how this matches up with the third piece of information your teacher provided

The third column is already done, but again we can see that 40+60 = 100.

Furthermore, the first two items of the third row add to 45+55 = 100 which helps confirm our answers.

The full completed table is shown below.

------------------------

To summarize, we are effectively just sorting the values given to us to write them into the table. Then we use a bit of algebraic detective work to find out what values are missing so we fill out the completed table.

7 0
3 years ago
Task: E = mc2
Afina-wow [57]

Answer:

$c=\left(\frac{E}{m} \right)^{\frac{1}{2} }$

Step-by-step explanation:

E = mc^2

$c^2=\frac{E}{m} $

$c=\sqrt{\frac{E}{m} } $

or

$c=\left(\frac{E}{m} \right)^{\frac{1}{2} }$

3 0
4 years ago
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