Answer:
Second puck travels farther
Step-by-step explanation:
Maximum height of first puck = 3 feet
The height of a second hockey puck is modeled by:
To find maximum height of second puck
Equate the derivative equals to 0
0.15-0.002x=0
75 = x
At x = 75
So, The maximum height of second puck is greater than first puck
So, Second puck travels farther
300 dollars would be the independent variable and 50 dollars a week is dependent
K-263.48=381.09
we add 263.48 on both sides
k=644.57
Answer: See the answers below.
The first equation that needs to be solve is: 10 = -16t^2 + 18
If you use the quadratic equation, you will get 0.707 seconds.
For the second equation, you need to solve 0 = -16t^2 + 18.
If you use the quadratic equation, you will get 1.061 seconds.
No, the rate of change is not constant because this is a quadratic equation.
Hey there! :)
Answer:
y = x - 3.
Step-by-step explanation:
Given:
Slope = 1
Point on line: (8, 5)
Plug these into the formula y = mx + b, where:
m = slope
x = x coordinate of point
y = y coordinate of point
5 = 1(8) + b
5 = 8 + b
Subtract both sides by 8:
5 - 8 = 8 -8 + b
-3 = b
Rewrite the equation:
y = x - 3.
