Which cannot be used in a proof?

Mathematics

2 answers:

IRINA_888 [86]3 years ago

7 0

Answer:

Undefined terms

Gwar [14]3 years ago

4 0

Hello,

you may not used what you are going to prove in a proof (la thèse)

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PLZ CAN SOMEONE ANSWER THIS !!

Cerrena [4.2K]

Answer:

(-4,2)

Step-by-step explanation:

First we have to find a common multiple to use to add and find the system of equations. We need to eliminate one of the variables in order to solve.

Since 5 * 3 = 15, and 3 * -5 = 15, -15x and 15x will cancel each other out. Therefore x will be eliminated.

Before:

5x + 2y = -16

3x + 7y = 2

After:

15x + 6y = -48 <----------Now we solve for y

-15x + -35y = -10

+----------------------

-29y = -58

-29 -29

y = 2

Now what we do is we choose and equation and solve for x, since it is still unknown. Any equation is fine but I will choose the second one since it has easy numbers.

3x + 7y = 2

3x + 7(2) = 2

3x + 14 = 2

-14 -14

----------------------

3x = -12

3 3

x = -4

Therefore our final answer is (-4,2)

5 0

3 years ago

Find the surface area of regular prism with height 6 cm, if the base of the prism is a Regular quadrilateral with side 4 cm.

marshall27 [118]

A "regular quadrilateral" is a square, so the length and width are both 4 cm. The surface area of a rectangular prism is given by
S = 2(LW +H(L +W))
S = 2((4 cm)*(4 cm) +(6 cm)*(4 cm +4 cm))
S = 2(16 cm² +48 cm²)
S = 2*64 cm² = 128 cm²

The surface area of the prism is 128 cm².

6 0

2 years ago

On the scale model, the distance between the wheels on the left and the wheels on the right is 1 1/4 inches. The state of Wyormi

avanturin [10]

Answer:

No, modern train cannot travel on old railroad.

Step-by-step explanation:

In rail transport, track gauge is the spacing of the rails on a railway track and is measured between the inner faces of the load-bearing rails.

Most of the modern train are based on broad gauge. The separation in broad gauge is about 5 ft and 6 inches and in the standard gauge the separation between the tracks is 4 ft and $8\frac{1}{2}$ inches. So for the modern train it is not possible to travel on the tracks whose separation is no more than 4.5 feet.