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2 years ago

Which cannot be used in a proof?

Mathematics

2 answers:

IRINA_888 [86]2 years ago

7 0

Answer:

Undefined terms

Gwar [14]2 years ago

4 0

Hello,

you may not used what you are going to prove in a proof (la thèse)

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What is the explicit formula for this sequence?

SVEN [57.7K]

Answer:

The correct answer is b.)

Step-by-step explanation:

Given:

Sequence -7, -4, -1, 2, 5....... => a₁ = -7, a₂ = -4, a₃ = -1, a₄ = 2 and a₅ = 5

We conclude that this sequence is arithmetic series.

First we must find difference d:

d = a₂ - a₁ = a₃ - a₂ = -4 - (-7) = -1 - (-4) = -4 + 7 = -1 + 4 = 3

d = 3

The formula for n-th term of the arithmetic series is:

aₙ = a₁ + (n-1) d

aₙ = -7 + (n-1) 3

God with you!!!

4 0

2 years ago

There’s a full 12 piece pizza. Ayla got a slice of pizza and John got 1 and two half’s of pizza.....how many slices are left.

Ghella [55]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Solve the equation. StartFraction dx Over dt EndFraction equals StartFraction 1 Over x e Superscript t plus 7 x EndFraction An i

MAVERICK [17]

Answer:

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

Step-by-step explanation:

We are given that

$\frac{dx}{dt}=\frac{1}{xe^{t+7x}}$

We have to find the implicit function

Using separation variable method

$\frac{dx}{dt}=\frac{1}{xe^t\cdot e^{7x}}$

By using property $x^a\cdot x^y=x^{a+y}$

$xe^{7x}dx=e^{-t}dt$

By using property $\frac{1}{x^a}=x^{-a}$

Taking integration on both sides

$\int xe^{7x}dx=\int e^{-t}dt$

Parts integration method

$\int u\cdot v dx=u\int vdx-\int (\frac{du}{dx}\int vdx)dx$

By parts integration method

$x\int e^{7x}dx-\int (\frac{dx}{dx}\int e^{7x}dx)dx=-e^{-t}+C$

Using formula $\int e^{ax} dx=\frac{e^{ax}}{a}+C$

$\frac{xe^{7x}}{7}-\frac{1}{7}\int e^{7x}dx=-e^{-t}+C$

$\frac{xe^{7x}}{7}-\frac{1}{49}e^{7x}+e^{-t}=C$

$\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

We are given that

$F(x,t)=C$

$F(x,t)=\frac{1}{49}(7x-1)e^{7x}+e^{-t}=C$

8 0

3 years ago

Help please 10 points!

Alinara [238K]

Answer:

I'm not sure, but it might be 120.

4 0

3 years ago

Are the graphs of the lines in the pair parallel?<br> Y=6x + 9<br> 27x - 3y= -81

kifflom [539]

No, the graphs of the lines are not parallel because if you simplify 27x-3y=-81, you get y=9x+27, and in order to have the lines parallel, both equations must have the same "m" in y=mx+b. 6 and 9 do not equal, so no they are not parallel.

7 0

3 years ago