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sergeinik [125]
2 years ago
5

If 20% of a school was made up of out-of-district students last year, but the number of out-of-district students increased by 50

% this year, without any change in total enrollment, what percent of the students is out-of-district this year?
Mathematics
1 answer:
Nadya [2.5K]2 years ago
4 0

Answer:

<h2>30% is enrolled out-of-district.</h2>

Step-by-step explanation:

According to the word problem, the number is increased by 50%.

To increase a number by a percent, multiply the number and the percent.

We can do this by changing both percents to decimals.

To change a percent to a decimal, divide it by 100.

20/100 = 0.2

50/100=0.5

The number is INCREASED by 50% so 0.5 would become 1.5.

0.2 * 1.5=0.3

<h2>0.3 = 30%.</h2>
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777dan777 [17]
The solution for this question would be. x += 5 hope it helps, and im truly am sorry if its incorrect!
8 0
2 years ago
Find an equation of the line in the form ax+by=c whose​ x-intercept is 12 and​ y-intercept is 4​, where​ a, b, and c are integer
Lostsunrise [7]

Answer:

The equation of the line  in ax+by=c  form where a,b,c  are integers with no factor common to all​ three, and greater than or equal 0 is:

x+3y=12

Step-by-step explanation:

Given:

x-intercept = 12

y-intercept = 4

To find the equation of line in the form ax+by=c where a,b,c  are integers with no factor common to all​ three, and greater than or equal 0.

Solution:

The x-intercept is the point at which the line cuts the x-axis. The point of x-intercept is given as (x,0)

Thus, on point of the line is (12,0)

The y-intercept is the point at which the line cuts the y-axis. The point of y-intercept is given as (0,y).

Thus, on point of the line is (0,4)

Using the two points we can find the slope of the line using the slope formula.

m=\frac{y_2-y_1}{x_2-x_1}

So, slope of the line can b given as:

m=\frac{4-0}{0-12}

m=\frac{4}{-12}

m=-\frac{1}{3}

The slope intercept form of the equation of he line is given as:

y=mx+b

where m represents slope of the line and b represents the y-intercept.

So, the equation of the line can be given as:

y=-\frac{1}{3}x+4

Multiplying each term by 3 to remove fraction.

3y=3.-\frac{1}{3}x+4(3)

3y=-x+12

Adding x both sides.

3y+x=-x+x+12

3y+x=12

Thus, the equation of the line  in ax+by=c  form where a,b,c  are integers with no factor common to all​ three, and greater than or equal 0 is:

x+3y=12

8 0
3 years ago
Does anyone know this??
blagie [28]

Answer:

x = 38, y = 4

Step-by-step explanation:

Since AB = BC  then the triangle is isosceles and the base angles are congruent, that is

∠ DAB = ∠ DCB = 52°

Subtract the sum of the base angle from 180° for ∠ ABC

∠ ABC = 180° - (52 + 52)° = 180° - 104° = 76°

Note that ∠ ABD = ∠ CBD, thus

x = 76 ÷ 2 = 38

BD bisects the side AC, thus DC = AD = 4

Thus y = 4

5 0
3 years ago
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
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mr_godi [17]

Answer:

Step-by-step explanation:

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2 years ago
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