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serious [3.7K]
3 years ago
7

I need help finding this answer to this inequality -10[9-2x]-x≤2x-5

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

x≤5

Step-by-step explanation:

-10(9-2x)-x≤2x-5

-90+20x-x≤2x-5

19x-2x≤90-5

17x≤85

x≤85/17

x≤5

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Help please not much time!!!!
Rzqust [24]

Answer:

I'm here! This Problem is easy :) The answer is 4

Step-by-step explanation:

2x+10=5x−2

<em>Subtract </em>5x from both sides

2x+10−5x=−2

<em>Combine</em> 2x and −5x to get −3x.

−3x+10=−2

Subtract 10 from <em>both sides.</em>

−3x=−12

<em>Divide</em> both sides by −3.

Divide −12 by −3 to get 4.

x=\frac{-12}{-4}

x = 4 (D)

7 0
3 years ago
Whats he approximete value of the square root of 8
Neporo4naja [7]

Answer:

the approximate value of the square root of 8 is 2.828

8 0
3 years ago
What is the next term of the geometric sequence?<br> 2, 10, 50,
Taya2010 [7]

Answer:

5

Step-by-step explanation:

2*5=10

10*5=50

5 0
3 years ago
Read 2 more answers
Which of the following is a way that you would employ arithmetic in a real world situation?
otez555 [7]

Hey there! The answer is actually A. Choosing a grocery item based on a price per unit comparison.

I hope this helps you guys!

I have a screenshot attached as proof :)

4 0
3 years ago
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Assume that the weights of spawning Chinook salmon in the Columbia river are normally distributed. You randomly catch and weigh
s344n2d4d5 [400]

Answer: The point estimate for the mean weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample (\overline{x}) = 31.2 pounds .

Step-by-step explanation:

The weights of spawning Chinook salmon in the Columbia river are normally distributed.

Given :  The mean weight from your sample is 31.2 pounds with a standard deviation of 4.4 pounds.

The point estimate for the mean (\mu) weight of all spawning Chinook salmon in the Columbia River is the mean weight from your sample (\overline{x}) i.e. is 31.2 pounds because the best point estimate for population mean is the sample mean. [in normal distribution]

8 0
3 years ago
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