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myrzilka [38]
3 years ago
14

Find the domain of x2-49/x2-4x-12

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0

Answer:

-4 i dont know how to explain but i wanned to get you the answer fast trust me its -4

Step-by-step explanation:

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Evaluate. <br><br> −7×(−6)×5=<br> -7×(-6)×5=<br> ______
Lunna [17]

Answer:

210

Step-by-step explanation:

double negatives = positive

-7 * -6 * 5 = 7 * 6 * 5 = 42* 5 = 210

7 0
3 years ago
What is the gcf of 64 and 16
Naily [24]
The gcf of 64 and 16 is16
6 0
2 years ago
Find the arc length of the 3/4 of a circle with a radius of 5
IgorLugansk [536]

Answer:

7.5 pi

Step-by-step explanation:

The formula for arc length of a sector is denoted as

\frac{x}{360}2\pi r, where x is the central angle of the sector.

Since the sector is 3/4 of a circle, the central angle will be 3/4 of 360 degrees.

3/4 of 360 is 270, so we have our central angle. We also have our radius which we can plug into the formula.

\frac{270}{360}2(5)\pi

2 times 5 is equal to 10, and 270/360 simplifies to 3/4. 3/4 times 10 is equal to 7.5, so the answer is 7.5 pi

3 0
3 years ago
On a cold winter day the temperature was -1 below zero. At night the temperature be dropped 4. What was the final temperature
Savatey [412]

Answer:

-1 + -4 = -5 below zero....If the temperature is -1 + 4 the temperature would be 3 degrees (-1+4=3)

Step-by-step explanation:

If the temperature is -1 + -4 = -5 below zero (adding two negatives equal a negative number).

If the temperate is -1 + 4 = 3 (+4-1=3) The number is positive because it is larger than the negative number.

4 0
2 years ago
Simplify the expression given below. x+2/4x^2+5x+1 * 4x+1/x^2-4
GenaCL600 [577]

Answer:

\frac{1}{(x+1)(x-2)}

Step-by-step explanation:

\frac{x+2}{4x^2 + 5x + 1} \ \times \ \frac{4x+1}{x^2-4}\\\\=\frac{x+2}{4x^2 + 4x  + x + 1} \ \times \ \frac{4x+1}{x^2-2^2}\\\\=\frac{x+2}{4x(x + 1)  + 1( x + 1)} \ \times \ \frac{4x+1}{(x - 2)(x + 2)}    \ \ \ \ \  \ \ \ [ \ (a^2 - b^2 = (a-b)(a+b) \ ]\\\\\\=\frac{x+2}{(4x + 1)(x+1)} \ \times \ \frac{4x+1}{(x-2)(x+2)}\\\\=\frac{1}{(x+1)} \ \times \ \frac{1}{(x-2)}\\\\= \frac{1}{(x+1)(x-2)}

8 0
3 years ago
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