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3 years ago

in a local coed softball keague, male to female ratio is 6:6. if there is 160 players in the league, how many are female?

Mathematics

1 answer:

Nonamiya [84]3 years ago

4 0

80. Bc a 6:6 ratio is also a 1:1. So half of 160 them would be female.

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A restaurant has 100 tables and 28 of the tables seat 2 people and 72 of the tables seat 4. What percentage of the tables seat 4

KiRa [710]

The percentage would be 72.

5 0

3 years ago

a houswwife bought one bag of grapes for $250. She retailed the grapes at $15 for one cup.She sold 65 cups of grapes and she use

Andru [333]

Answer:

$725

Step-by-step explanation:

First, find how much money she made from selling 65 cups:

65(15)

= 975

Subtract the $250 that she spent on the bag of grapes:

975 - 250

= 725

So, her profit was $725

5 0

3 years ago

Determine what type of model best fits the given situation:

lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = $\frac{20}{100} \times P = 0.2P$

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = $\frac{20}{100} \times 0.8P = (0.2)(0.8P)$

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

$=P(0.8)^{2}$ -------------------------(2)

Similarly after 3 years, this value $P(0.8)^{2}$ will again be decreased by 20 %

so 20% of $P(0.8)^{2} \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}$

So after 3 years value is decreased by $(0.2)P(0.8)^{2}$

so value after 3 years will be = $P(0.8)^{2} - (0.2)P(0.8)^{2}$

taking $P(0.8)^{2}$ common out we get $P(0.8)^{2}(1-0.2)$

$P(0.8)^{2}(0.8)$

$P(0.8)^{3}$ -----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or $P(0.8)^{1}$

value after 2 years is $P(0.8)^{2}$

value after 3 years is $P(0.8)^{3}$

so value after x years will be $P(0.8)^{x}$ ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

$y = P(0.8)^{x}$ where y is the value after x years

so thats the final answer

3 0

4 years ago

Paulie is buying a shirt that was originally priced at $15. The store has a today-only discount of 25%. What is today’s price fo

fenix001 [56]

Answer:

he is buying it for 11.25. you get this buy multiplying 15 by 25% which equals 3.75 then you subtract 15 by 3.75 and you get 11.25

hope it helps

please mark as brainliest

Step-by-step explanation:

3 0

3 years ago

Bob took out a 5 year loan for $4000 and paid 3% annual simple interest

tankabanditka [31]

Answer:

Sum = $1400

Step-by-step explanation:

Given the following data;

I. For Bob;

Principal, P = $4000

Interest rate, R = 3%

Time, T = 5years

To find the simple interest, we would use the following formula;

S.I = PRT/100

Substituting into the formula, we have;

S.I = 4000*3*5/100

S.I = 40 * 15

S.I = $600

II. For Bill;

Principal = $4000

Interest rate = 5%

Time = 4years

To find the simple interest;

S.I = PRT/100

S.I = 4000*5*4/100

S.I = 40 * 20

S.I = $800

III. Sum of amounts of interest for both;

Sum = 600 + 800

Sum = $1400

Therefore, the sum of amounts of interest bob and bill paid for their loans is $1400.

3 0

3 years ago