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3 years ago

Simplify 3(7-3) the second power -4(6+2)

Mathematics

2 answers:

expeople1 [14]3 years ago

8 0

Answer:

112

Step-by-step explanation:

3(7-3) = 3 x 4 = 12

12^2 = 144

144 -4(6+2)

144-4(8)

144-32

112

MariettaO [177]3 years ago

7 0

$\bf \stackrel{\mathbb{P~E~M~D~A~S}}{3(7-3)^2-4(6+2)}\implies 3(\stackrel{\downarrow }{4})^2-4(\stackrel{\downarrow }{8})\implies 3(\stackrel{\downarrow }{16})-4(8) \\\\\\ \stackrel{\downarrow }{48}-4(8)\implies 48-\stackrel{\downarrow }{32}\implies 16$

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A farmer is going to divide her 30 acre farm between two crops. Seed for crop A costs $5 per acre. Seed for crop B costs $10 per

jenyasd209 [6]

Answer:

30 acres of A

0 acres of B

Step-by-step explanation:

On forming the equations we get

Acres = A+B $\leq$ 30 .............(1)

Seed = 5A + 10B $\leq$ 200 ...........(2)

Profit = 160A+50B

Upon rearranging this we get

A= 30-B sing equation (1)

A=40-2B using equation (2)

On plotting these inequalities on the cartesian planes we will get the following points of intersection (0,20) (20,30) (30,0)

Now using these coordinates (A,B) to get Maximum profit

P= $1000 for (0,20)

P=$4700 for (20,30)

P= $4800 for (30,0)

clearly for (30,0) we will get the maximum profit on the crops

3 0

3 years ago

A scientist is observing the grizzly bear population in two state parks. The parks each have 150 bears when he begins observing

Mars2501 [29]

Nothing to drag; nowhere to drag it to.

Park A's population can be modeled by
.. y = 150*1.2^x

Park B's population can be modeled by
.. y = 150*0.8^x

5 0

3 years ago

Read 2 more answers

I need the steps and solution <br>-10x + 5y = 10 <br>x - 5y = -28

natta225 [31]

−10x+5y=10

x−5y=−28

Rewrite equations:

x−5y=−28

−10x+5y=10

Step: Solve:

x−5y=−28

x−5y+5y=−28+5y(Add 5y to both sides)

x=5y−28

Step: Substitute:

−10x+5y=10

−10(5y−28)+5y=10

−45y+280=10(Simplify both sides of the equation)

−45y+280+−280=10+−280(Add -280 to both sides)

−45y=−270

−45y

−45

−270

−45

(Divide both sides by -45)

y=6

Step: Substitute:

x=5y−28

x=(5)(6)−28

x=2(Simplify both sides of the equation)

Answer:

x=2 and y=6

6 0

2 years ago

Kathy dropped a snowball from a building that is 39.2 meters tall. The equation t2 = 39.29.8 represents the amount of time, in s

DIA [1.3K]

Answer:

We note that the equation that is compatible with the given equation is the kinematic equation of free fall where;

t² = 39.2 × 2/9.81

From which we have;

The time it takes the snowball to reach the ground is approximately 2.83 seconds

Step-by-step explanation:

The height of the building from which the ball is dropped, h = 39.2 m

The equation of the dropped a snowball, is given as follows;

t² = 39.2 × 9.8

Using the From the equation of free fall, we have;

s = u·t + 1/2·g·t²

Where;

u = The initial velocity = 0 m/s

t = The time of flight

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we get;

∴ s = The height from which the snowball is dropped = 39.2 m

Therefore, we get;

39.2 = 0×t + 1/2×9.81×t²

∴ t² = 39.2 × 2/9.81 ≈ 7.99

t = √(7.99) ≈ 2.83

The time it takes the snowball to reach the ground, t ≈ 2.83 s.

8 0

2 years ago

Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$

The minimum initial velocity needed for the ball to clear the fence is $125.4\ \text{m/s}$

5 0

2 years ago