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3 years ago

What is the solution of the equation? 35√(x+2)3+3=27

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

4 0

Use this rule: <em>(x^a)^b = x^ab</em>

3(x + 2)^3/5 + 2 = 27

Subtract 3 from both sides

3(x + 2)^3/5 = 27 - 3

Simplify 27 - 3 to 24

3(x + 2)^3/5 = 24

Divide both sides by 3

(x + 2)^3/5 = 24/3

Simplify 24/3 to 8

(x + 2)^3/5 = 8

Take the cube root of both sides

x + 2 = 3/5√8

Invert and multiply

x + 2 = 8^5/3

Calculate

x + 2 = 2^5

Simplify 2^5 to 32

x + 2 = 32

Subtract 2 from both sides

x = 32 - 2

Simplify 32 - 3 to 30

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Solve for x in the equation x squared + 2 x + 1 = 17.

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Answer:

x = negative 1 plus-or-minus StartRoot 17 EndRoot

Step-by-step explanation:

Given:

$x^2+2x+1=17$

We need to solve for x.

$x^2+2x+1=17 \ \ \ \ equation\ 1$

First we will solve L.H.S

Factorizing the equation we get;

$x^2+2x+1\\=x^2+x+x+1\\=x(x+1)+1(x+1)\\=(x+1)(x+1)\\=(x+1)^2$

Now Things which are equal to the same thing are also equal to one another. Since

$x^2+2x+1=17$

$x^2+2x+1=(x+1)^2$

then, according to the law of transitivity,

$(x+1)^2=17$

Now, applying the Square Root Principle we get:

$\sqrt{(x+1)^2} =\sqrt{17}$

Now Square root and square gets cancelled.

$x+1=\sqrt{17} \\x=-1+\sqrt{17}$

Since a square root has two values, one positive and the other negative.

$x=-1\±\sqrt{17}$

Hence Final Answer is $x=-1\±\sqrt{17}$ .

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2 years ago

Given the triangle that has a base of five less than triple the height. The height is 2x+6.

Deffense [45]

Answer:

Step-by-step explanation:

H = 2x+6 - the hight

3H = 3(2x+6) - triple the hight

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3 years ago

0.25÷3=x÷1 1/2 That fraction is one and a half.

Sladkaya [172]

Answer:

Step-by-step explanation:

Given the expression 0.25÷3=x÷1 1/2, we are to look for the value of x from the given equation. Rewriting the equation we will have;

$\dfrac{0.25}{3} = \dfrac{x}{1\frac{1}{2} }$

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