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3 years ago

Milly has 636 shopkins arranged in 12 rows how many shopkins are in each row

Mathematics

2 answers:

kodGreya [7K]3 years ago

8 0

Divide 636 / 12 which equals 53 ?

svet-max [94.6K]3 years ago

7 0

Answer:

You answer it 53 because when you divide 636 by 12 you get 53

Step-by-step explanation:

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The cost of 5m of cloth is ₹450. The cost of 8m of cloth is

enyata [817]

Step-by-step explanation:

Rs 720

Cost of 1 m of cloth = 450/5= Rs 90

Cost of 8 m of cloth= 90*80= Rs 720

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3 years ago

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Use the drawing tools to form the correct answers on the grid.

Dafna1 [17]

Answer:

I don't understand the array of numbers as written in the question.

Step-by-step explanation:

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2 years ago

Given g(x)=3x+6 on what interval is the function negative

iris [78.8K]

Step-by-step explanation:

A number that is negative is less than 0, so

$3x + 6 < 0$

$3x < - 6$

$x < - 2$

So this function is negative, when x is less than -2

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2 years ago

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At Charles School, 1/5 of the 75 students in seventh grade play in the jazz band. how many seventh graders play in the jazz band

My name is Ann [436]

Answer: 15

Step-by-step explanation:

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3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago