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Ivahew [28]
3 years ago
15

What is the distance between -4.5 and 3.5

Mathematics
2 answers:
Aloiza [94]3 years ago
7 0
8 because 4.5 plus 3.5 is 8
iVinArrow [24]3 years ago
4 0
-8 hope this helps u :)
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The derivative of f(x) = e^xinx​
aksik [14]

Answer:

e^xsinx · (sinx+xcosx)

Step-by-step explanation:

f'(x)=e^xsinx · (xsinx)'= e^xsinx · (sinx+xcosx)

4 0
3 years ago
Greatest to least of 2, -1, -2, 0, 1
Wittaler [7]

Answer:

2,1,0,-1,-2

Step-by-step explanation:

4 0
3 years ago
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Mrs. Del Pup bought 20 yards of border for her classroom bulletin board.
KengaRu [80]

A rectangle with dimensions x and y has perimeter 20 if

2(x+y)=20 \iff x+y=10

and we can deduce

y=10-x

So, the dimensions of the rectangle must be x and 10-x, where x ranges from 0 to 10 (both extremes are excluded, otherwise you'd have a degenerate rectangle, which is actually a segment).

So, all the possible areas are given by the product of the dimensions, i.e.

x(10-x) = -x^2+10x

The function f(x)=-x^2+10x represents a parabola, facing downwards, and thus it admits a maximum, which is its vertex.

In particular, the vertex of this parabola is given by

x=\dfrac{-b}{2a}=\dfrac{-10}{-2}=5

And it yields an area of

f(5)=-25+50=25

(a) So, she can frame a maximum area of 25 squared yards.

(b)The dimensions of the rectangle with greatest area are x=5 and y=10-x=10-5=5, so it's actually a square.

This is a well known theorem: if you fix the perimeter, the rectangle with the largest area is the square yielding that perimeter.

(c) If we increase both dimensions by 2 yards, our 5x5 square would become a 7x7 square...

(d) ...and the new area would be 7^2=49 squared yards. So, the new area is 49-25=26 squared yeards more than the old one.

6 0
3 years ago
HELP!! What is the exact value of Tangent (pi/12)
Vlad1618 [11]

Answer:

2 - sqrt(3)

Step-by-step explanation:

Split pi/12 into two angles where the values of the six trigonometric functions are known.

tan (pi/4 - pi/6)

Apply the difference of angles identity

\frac{tan(pi/4) - tan(pi/6)}{1 + tan(pi/4)tan(pi/6)}

tan(pi/4) = 1 , tan(pi/6) = (sqroot3)/3

Plug in and Simplify

\frac{1-\frac{\sqrt{3} }{3} }{1+1\frac{\sqrt{3} }{3} }

\frac{\frac{3-\sqrt{3} }{3} }{\frac{3+\sqrt{3} }{3} }

\frac{3-\sqrt{3} }{3} *\frac{3}{3+\sqrt{3} }

\frac{3-\sqrt{3} }{3+\sqrt{3}} Need to multiply this by \frac{3+\sqrt{3} }{3+\sqrt{3} }

Expand and simplify numerator: \frac{6}{(3+\sqrt{3} )^{2} }

Expand and simplify denominator: \frac{6}{12+6\sqrt{3}}

Cancel the common factor: \frac{1}{2+\sqrt{3}}

6 0
3 years ago
Read 2 more answers
Pls help i really need to get this done
nataly862011 [7]
The answer to this is c
6 0
3 years ago
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