Which equation shows the distributive property?

The width of a computer is 1.25 times its height. Find the height of the computer monitor at the right. Use a bar diagram to sol

MariettaO [177]

The answer is 15 inches. If you let h stand for the height. Set them equal. 1.25 = 15. divide both sides by 1.25. h = 12

8 0

3 years ago

Complete these two different sets of data so that they each have six values and a mean of 21 . 20,20.5,20.5,21.5,21.5, 20,21,21,

jeka57 [31]

Answer:

The complete first set is;

20, 20.5, 20.5, 21.5, 21.5, 22

The complete second set is;

20, 21, 21, 21, 21, 22

Step-by-step explanation:

The mean or the average value of a data set is simply;

(sum of the values in the data set) / ( number of values in the set)

In the first set we are given the following values;

20,20.5,20.5,21.5,21.5

We are required to complete this set so that we have a total of 6 values with a mean of 21.

We let the sixth value be x. Going by the above definition of the mean we have the following equation;

$21=\frac{20+20.5+20.5+21.5+21.5+x}{6}$

We simplify the equation and solve for x;

$21=\frac{104+x}{6}\\126=104+x\\x=126-104\\x=22$

The complete set is thus;

20,20.5,20.5,21.5,21.5,22

In the second set we are given the following values;

20,21,21,21,21

We are also required to complete this set so that we have a total of 6 values with a mean of 21.

We let the sixth value be y. Going by the above definition of the mean we have the following equation;

$21=\frac{20+21+21+21+21+y}{6}$

We simplify the equation and solve for y;

$21=\frac{104+y}{6}\\126=104+y\\y=126-104\\y=22$

The complete set is thus;

20,21,21,21,21,22

8 0

4 years ago

The circumference of the equator of a sphere was measured to be 82 82 cm with a possible error of 0.5 0.5 cm. Use linear approxi

True [87]

Answer:

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

Step-by-step explanation:

The circumference ( $s$ ), in centimeters, and the surface area ( $A_{s}$ ), in square centimeters, of a sphere are represented by following formulas:

$A_{s} = 4\pi\cdot r^{2}$ (1)

$s = 2\pi\cdot r$ (2)

Where $r$ is the radius of the sphere, in centimeters.

By applying (2) in (1), we derive this expression:

$A_{s} = 4\pi\cdot \left(\frac{s}{2\pi} \right)^{2}$

$A_{s} = \frac{s^{2}}{\pi^{2}}$ (3)

By definition of Total Differential, which is equivalent to definition of Linear Approximation in this case, we determine an expression for the maximum error in the calculated surface area ( $\Delta A_{s}$ ), in square centimeters: