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Keith_Richards [23]
3 years ago
12

Write a balanced half-reaction describing the reduction of gaseous dichlorine to aqueous chloride anions.

Chemistry
1 answer:
Annette [7]3 years ago
4 0

Answer:- Cl_2(g)+2e^-\rightarrow 2Cl^-(aq)

Explanations:- In reduction the electrons are accepted and so they are written on the reactant side. When an atom accepts electrons then it forms anion. Chlorine has 7 valence electrons and it needs one more electron to complete it's octet. Since, dichlorine has two Cl atoms and each Cl atom needs one more electron to complete it's octet, two electrons are accepted by dichorine to make aqueous chloride ion. For balancing the equation, there would be two chloride ions as the reactant side has two chlorine atoms.

Cl_2(g)+2e^-\rightarrow 2Cl^-(aq)

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The bond between carbon and hydrogen is one of the most important types of bonds in chemistry. The length of an H—C bond is appr
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Answer:

The dipole moment of H-C bond will be smaller than that of an H-I bond.

Explanation:

The electronegativity of iodine is greater than that of hydrogen.As a result the iodine atom tends to attract the bond electron pair of H-I bond towards itself creating a bond dipole which does not occur in case of H-C bond as the electronegativity of carbon and hydrogen are almost same.

   That"s why dipole moment of H-C bond is smaller than that of H-I bond.

7 0
3 years ago
The speed of light is 300,000,000 m/s. What is the frequency of microwaves with a wavelength of 0.01 meter?
elixir [45]

Answer:

30,000,000,000 Hz

Explanation:

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3 years ago
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A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin
lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, 3.0\times 10^1g

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron metal = 0.45J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron metal = 32.3 g

m_2 = mass of water = ?

T_f = final temperature of mixture = 59.2^oC

T_1 = initial temperature of iron metal = 21.9^oC

T_2 = initial temperature of water = 63.5^oC

Now put all the given values in the above formula, we get

32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC

m_2=30.16g\approx 3.0\times 10^1g

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3 0
3 years ago
What is the mass of 1.6x1020 molecules of carbon dioxide?
valentina_108 [34]

Answer:

1.2*10^{-2} g

Explanation:

1 mol - 6*10^{23} particles

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44\frac{g}{mol} *0.00026578 mol =0.012 = 1.2*10^{-2} g

8 0
3 years ago
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