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Softa [21]
3 years ago
10

When Earth’s Plates shift the result is a(n)______.

Chemistry
2 answers:
olga_2 [115]3 years ago
8 0

Answer:

The correct answer is (lava)

Explanation:

Youre welcome    

When the plates move they collide or spread apart allowing the very hot molten material called lava to escape from the mantle. When collisions occur they produce mountains, deep underwater valleys called trenches, and volcanoes.

Ivenika [448]3 years ago
7 0

Answer:

An earthquake could occur.

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On average, Earth’s crust contains about 8.1% aluminum by mass. If a standard 12-ounce soft drink can contains approximately 15
MrMuchimi

Answer:

5400 cans

Explanation:

First we convert the total weight, 1 ton, to grams:

1ton=1x10^{6}g

Now we need to know the mass of aluminum:

m_{Al}=\frac{10^{6}*8.1}{100} =81000g

Now we make the relation between the mass of aluminum in 1 ton of the earth's crust and the mass of aluminum per can:

n=\frac{81000g}{15g/can} =5400cans

8 0
4 years ago
During the phase change from solid ice to liquid water, which bonds/forces are being weakened?
vampirchik [111]
I think Intramolecular forces are being weakened
5 0
3 years ago
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How many moles of carbon dioxide gas can be produced when 7.94 moles of benzene (C6H6) react with excess oxygen? Be sure to show
Sliva [168]
The balanced equation is 

<span>2 C6H6 +15 O2 = 12 CO2 + 6 H2O </span>

<span>the ratio between C6H6 and CO2 is 2 : 12 </span>

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4 years ago
The state of water is determined solely by the conditions of _____.
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3 years ago
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To understand the relation between the strength of an acid or a base and its pKa and pKb values. The degree to which a weak acid
elena-14-01-66 [18.8K]

Answer:

pKa = 3.675

Explanation:

  • pKa = - Log Ka

∴ <em>C</em> X-281 = 0.079 M

∴ pH = 2.40

let X-281 a weak acid ( HA ):

∴ HA ↔ H+ + A-

⇒ Ka = [H+] * [A-] / [HA]

mass balance:

⇒<em> C</em> HA = 0.079 M = [HA] + [A-]

⇒ [HA] = 0.079 - [A-]

charge balance:

⇒ [H+] = [A-] + [OH-]... [OH-] is negligible; it comes from to water

⇒ [H+] = [A-]

∴ pH = - log [H+] = 2.40

⇒ [H+] = 3.981 E-3 M

replacing in Ka:

⇒ Ka = [H+]² / ( 0.079 - [H+] )

⇒ Ka = ( 3.981 E-3 )² / ( 0.079 - 3.981 E-3 )

⇒ Ka = 2.113 E-4

⇒ pKa = - Log ( 2.113 E-4 )

⇒ pKa = 3.675

8 0
3 years ago
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