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Stells [14]
3 years ago
13

A map has a scale of 1 cm : 9 km. If two cities are 10 cm apart on the map, what is the actual distance between the cities, to t

he nearest tenth of a kilometer?
Mathematics
1 answer:
Ymorist [56]3 years ago
8 0
We can solve this problem by the rule of three:
1 cm-----------------9 Km
10 cm----------------  x

x=(10 cm * 9 km) / 1 cm=90.0 Km.

answer: 90.0 Km
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18x/18 = 2/3 • 18
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Locate the point on the line segment between A(3, -5) and B(13, -15) given that the point is 4/5 of the way from A to B. Show yo
SVETLANKA909090 [29]

Answer:

C ( 11 , -11 )

Step-by-step explanation:

Solution:-

We are given two points in the cartesian coordinate system as:

                   A ( 3 , -5 )              B ( 13 , -15 )

The point C lies on the line segment from A to B. The ratio of segment given is:

                              AC / AB = 4 / 5

To solve such type of problems. We will use vector equation of line AC.

To form a vector equation of line representing AB. We will first determine the direction vector ( d ) that is parallel to the line AB as follows:

                 d = OB - OA

                 d = < 13 , -15 > - < 3 , -5 >  

                 d = < 10 , -10 >

The fixed point on the line is taken. We will take point A. The vector equation of line from point A to point B is expressed as:

                < x , y > = OA + s*d

                < x , y > = < 3, -5 > + s* < 10 , -10 >  

The above equation satisfies all the points that lies on the line AB. To determine the coordinates of ( C ). We will plug in the appropriate value of parameter ( s ) and evaluate.

So point C is 4/5 th the magnitude of the distance AB from A. Hence, s = 4/5 as follows:

               < x , y > = < 3 , -5 > + ( 4/5 ) * < 10 , -10 >  

               < x , y > = < 3 , -5 > + < 8 , -8 >  

              < x , y > = < 11 , -11 >   ... Answer

8 0
3 years ago
The range of the function RK) = R +26+1 İS {25, 643. What is the function's domain?
frozen [14]

Answer:

A

Step-by-step explanation:

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