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Hunter-Best [27]
3 years ago
7

How could human activity disrupt the habitat and niche of an organism like the gray fox?

Biology
1 answer:
BlackZzzverrR [31]3 years ago
4 0

Answer:

Disruption such as deforestation or mining can destroy the habitat, leading to water pollution, mud slides, and loss of soil. With the habitat affected, the animals the grey fox feeds on, such as rabbits or mice, will be affected as well, leading to the grey fox losing a source of food. By limiting the diet of the grey fox, other predators will be more likely to compete with the grey fox, disrupting its niche.

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Which of the following chromosome pairings would a normal female duck have?
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Answer:  ZW

The sex chromosomes in birds are known as Z and W, and the presence of a W chromosome causes the development of a female <u>(ZW).</u>

Explanation:  ducks are cute tho lol

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Mrs. smith has blood type
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1/3 probability would be the answer
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Your biology teacher has asked you to do the impossible! You must measure the diameter of one algal cell. You are about to turn
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4- Jamie does an experiment. She charges a pencil by rubbing it with a piece
lyudmila [28]

Answer:

More info given below.

Explanation:

This attraction occurs as a result of static charge. You see an atom is referred to as the smallest particle of a substance; and when an atom gains or looses electrons it becomes unstable creating a difference in potential. However in this case rubbing induces friction which induces heat. This heat excites the atom to loose electrons creating a negative charge on the silk and a converse positive charge on the pencil.

3 0
2 years ago
A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by
bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that  <em>the</em><em> probability</em><em> that, given enough time, all tigers in the population will have horizontal stripes is</em><em> 30% = 0.3.</em>

--------------------------

<u>Available data:</u>

  • Population size, N = 100 tigers
  • Number of Tigers with horizontal stripes = 30
  • Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

--------------------------

You can learn more about Hardy-Weinberg equilibrium at

brainly.com/question/12724120?referrer=searchResults

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brainly.com/question/419732?referrer=searchResults

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brainly.com/question/5028378?referrer=searchResults

6 0
2 years ago
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