This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :
Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.
Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
The sentence in numerical form is 5x/7≤10
to solve, multiply by 7
5x≤70
lastly, divide by 5
x≤14
Answer:
The x-intercept is (-6, 0) and the y-intercept is (0, 2)
Step-by-step explanation:
We are already given points where x = 0 and y = 0
The x-intercept is when y = 0
The y-intercept is when x = 0
So the x-intercept is (-6, 0)
and the y-intercept is (0, 2)
Greetings and Happy Holidays!
<span>
1) Perpendicular to </span>
In order for lines to be
perpendicular, their slopes must be
negative reciprocals.Example of slopes with negative reciprocals: 5 and
First,
rearrange the equation into
slope y-intercept form:
The
slope of the equation is: \frac{1}{5}
The
negative reciprocal formula:
Solve for the negative reciprocal:
Divide both sides by
The slope of the new line is:
-5
2) Passes through (-5,-2)
Create an equation with the slope discovered in slope y-intercept form.
Input the point the line passes through.
Solve for b (the y-intercept).
Multiply.
Add -25 to both sides.
The y-intercept is equal to
-27
The Equation of the line is:
I hope this helped!
-Benjamin