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zysi [14]
2 years ago
7

Inez and Joe worked at store that sells cell phones.Inez worked for 7 hrs and 23 minutes and Joel worked for 4 hrs and 51 minute

s. How much longer did Inez work than Joe?
Mathematics
1 answer:
Paul [167]2 years ago
4 0

Answer:

Inez worked for 2 hours 32 minutes more than Joe

Step-by-step explanation:

Here, we are to calculate the difference in the amount of time in which both of them spent working.

Mathematically, that would be the time spent by Inez minus the time spent by Joe

= 7 hrs 23 minutes - 4 hrs 51 minutes

This works like normal arithmetic subtraction;

Since we cannot subtract 51 minutes from 23 minutes, we need to borrow 1 hour ( 60 minutes) from 7 , and it becomes 6 while our minutes become (60 + 23 = 83 minutes).

So the difference here will be (6-4)hrs and (83-51) minutes = 2 hrs 32 minutes

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Should be 7.5% I have to add more words to this sentence to post it
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1 year ago
molly is painting a model house and needs to know how much paint she will need. she knows the surface area of the prism is 216 s
Andrej [43]

Answer:

Part 1) The surface that is shared by the two solids is the top of the cube that is the same that the square base of the pyramid.

Part 2) The dimensions of this surface are 6 in x 6 in.

Part 3) Molly needs to paint 228 square inches.

Step-by-step explanation:

Part 1) Which surface is shared by the two solids?

we know that The surface that is shared by the two solids is the top of the cube that is the same that the square base of the pyramid

Part 2)  What are the dimensions of this surface?

The surface is a square with side length 6 inches so The dimensions of this surface are 6 in x 6 in

Part 3) what is the area molly needs to paint?

we know that The area that Molly needs to paint is equal to the surface area of the cube plus the surface area of the pyramid minus two times the area of the surface that is shared by the two solids so therefore, Molly needs to paint 228 square inches

8 0
3 years ago
Help me with a. b. c. I need help
hammer [34]

Answer:

a) Perimeter = 20.5 Inches

   Area is 15 Sq Inches

b) Perimeter is 61.4 Cms

    Area is 210 Sq cm

c) Perimeter is 22 yards

   Area is 21 Sq Yards

Step-by-step explanation:

a) Perimeter = sum of all the sides

= 8+7.5+5

=20.5

Perimeter = 20.5 Inches

Area of Triangle =\frac{1}{2} \times height \times Base

Base = 7.5 In

Height = 4 In

A = \frac{1}{2} \times 4 \times 7.5

A = 2 \times 7.5

A = 15

Hence Area is 15 Sq Inches

b)  Perimeter = Sum of all the sides

P=13+23+13.4+12

P=61.4

Perimeter is 61.4 Cms

Area of trapezium = \frac{1}{2} \times height  \times (sum \ of \ parallel \ sides)

A= \frac{1}{2} \times 12 \times (12+23)

A= 6 \times 25

A=210

Area is 210 Sq cm

c) Perimeter = Sum of all the sides

P = 7+4+7+4 ( as Opposite sides are equal in a parallelogram

P = 22

Perimeter is 22 yards

Area of a parallelogram = base \times height

A= 7 \times 3

A = 21

Area is 21 Sq Yards

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Answer:

(x-17)

Step-by-step explanation:

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