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Marizza181 [45]
3 years ago
7

Suppose that the scatterplot shows the response time from websites when computers communicate through the Internet. Paul use the

equation y=1/50x+15 to model the data in the scatterplot. According to the linear model, what is the predicted response time for a computer 2000 Miles away
*1/50 x is supposed to represent a fraction with the variable x*

Mathematics
1 answer:
lukranit [14]3 years ago
3 0
It’s gonna be 300 idk how to explain but it is 300
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Let v = −5 and w = 0.
sammy [17]

Answer:

c

Step-by-step explanation:

sorry if wrong

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In a parking garage the number of suv's is 40% greater than the number of automobiles. there are 98 suv's. how many automobiles
chubhunter [2.5K]
A=automobile S=SUV
0.4A+A=98 (to change a percent to a decimal you move the decimal point two places to the right)
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16 divided 18 = 3 divided n
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7 0
3 years ago
Read 2 more answers
Please and thank you
vampirchik [111]

Answer:

is this free points. cuz why you said please and thank you?

Step-by-step explanation:

7 0
3 years ago
3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie
allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x  = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 53^\circ=\frac{150-x}{h}

\displaystyle \tan 48^\circ=\frac{x}{h}

From the last equation:

x=h.\tan 48^\circ

Substituting into the first equation:

\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}

Operating on the right side:

\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ

Rearranging:

\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}

Solving for h:

\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0
3 years ago
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