Problem 3
<h3>Answer: 1/5 of a gallon per minute</h3>
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Explanation:
Two points from the graph are (10,2) and (20,4)
Apply the slope formula
m = (y2-y1)/(x2-x1)
m = (4-2)/(20-10)
m = 2/10
m = 1/5
The slope of the graph is 1/5.
Do the same for two points from the table. I'll use the first two rows
m = (y2-y1)/(x2-x1)
m = (4-2)/(10-5)
m = 2/5
The slope of the table is 2/5.
Subtract the two slopes to wrap things up:
2/5 - 1/5 = (2-1)/5 = 1/5
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Problem 5
<h3>Answer:
23 degrees</h3>
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Explanation:
Angles 1 and 3 are same side exterior angles, so they are supplementary due to the parallel lines set up here.
(angle1)+(angle3) = 180
(157) + (angle3) = 180
angle3 = 180-157
angle3 = 23 degrees
Answer:
The relationship in this equation is linear, but not proportional. If it was proportional, then replacing x with nx should give ny as the answer. Example:
y = 3x
Replace x with 2x.
y' = 3(2x) = 2(3x) = 2y
y' = 2y
This is proportional. But if you replace x with 2x in
y = 3x + 5,
you will not get 2y for y'. This case is not proportiona
<span>-2.7 is a rational number, since it is expressed as a terminating decimal. It is NOT a natural number, whole number, integer. It is NOT an irrational number. It is also a REAL number
(I think Im correct, Im sorry if not)</span>
9.28 plus 2 is 11.28. 1/4 of 18 is 4.50. Add 4.50 to 9.28 and your total is $15.78.
The equation would be:
9.28+18(.25)+2=c
Answer:
<h2> 5880 joules</h2>
Step-by-step explanation:
Given data
mass of rock, m= 200 kg
height/distance = 3 m
Now we know that the expression for work done is
w= force* distance
and also we need to find the force exerted by mass of rock
F= mg
Substituting our data and solving for force we have (assuming g= 9.81 m/s^2)
Force= 200*9.81
Force= 1962 N
Now we can find the work done
work done= 1962*3
work done= 5880 joules
