Question

Simplify 3 square root of 5 end root minus 2 square root of 7 end root plus square root of 45 end root minus square root of 28.

Answer 1

Answer:

The simplified expression is $6\sqrt5-4\sqrt7$

Step-by-step explanation:

We have been given the expression

$3\sqrt5-2\sqrt7+\sqrt{45}-\sqrt{28}$

Let us rewrite the numbers inside the square root as a product of two numbers in which at least one of them is a perfect square.

$3\sqrt5-2\sqrt7+\sqrt{9\times5}-\sqrt{4\times7}$

Now, we know that

$\sqrt9 = 3\text{ and }\sqrt4=2$

Thus, we have

$3\sqrt5-2\sqrt7+3\sqrt{5}-2\sqrt{7}\\\text{Combining the like terms, we get}\\6\sqrt5-4\sqrt7$

Answer 2

Simplify √ 45 to 3√ 5 and √ 28 to 2√ 7
Which gives you (3√5 +3√ 5 )+(−2√ 7 −2√ 7 )
Combine like terms = 6√ 5 −4√ 7
Done​​