Solve for x (x+7)^2-49=0 find the smaller and larger x smaller x= larger x=

2 answers:

8 0

$(x+7)^2-49=0\qquad\text{add 49 to both sides}\\\\(x+7)^2=49\iff x+7=\pm\sqrt{49}\\\\x+7=-7\ or\ x+7=7\qquad\text{subtract 7 from both sides}\\\\\boxed{x=-14\ or\ x=0}\\\\Answer:\\\\smaller\ x=-14\\larger\ x=0$

Alisiya [41]3 years ago

3 0

Answer:

x = -14 and x=0

Step-by-step explanation:

(x+7)^2-49=0

Add 49 to both sides

(x+7)^2-49+49=0+49

(x+7)^2 = 49

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(49)

(x+7) = ±sqrt(49)

x+7 = ±7

Subtract 7 from each side to isolate x

x+7-7 = -7±7

x = -7±7

x = -7+7 and x = -7-7

x = 0 and x=-14

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tankabanditka [31]

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<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

When two lines are parallel, they have the same slope. In this problem, the given line passes through (-5,-4) and (0,-3), hence the slope is:

m = (-3 - (-4))/(0 - (-5)) = 1/5.

Hence the equation is:

$y = \frac{x}{5} + b$