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3 years ago

Which equation represents a circle with a center at (-4,9) and a diameter of 10 units?

Mathematics

1 answer:

elixir [45]3 years ago

7 0

The first option is correct. See an explanation below.

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Enter the correct value so that each expression is a perfect-square trinomial.

Novosadov [1.4K]

If this is a perfect square trinomial, you want to look at your constant--36. the square root of 36 is 6, so your factors would be:

(x + 6)(x + 6) ... foil this, and see what your middle value is.
x² + 12x + 36 is your result. 12 is your middle term.

5 0

4 years ago

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Chuck must save a total of 180 for a new bike. So far he has saved 4/5 of the amount. How much money has chuck saved for the bik

4vir4ik [10]

He has saved $144 out of $180

6 0

3 years ago

Find the x- and y- intercepts of the graph of the linear equation 3x-6y=2

bogdanovich [222]

- Put x=0, you would get the y-intercept, so you got one point which would be (0,#)

- Put y=0, you got where the graph would touch\cross\intersect the x-axis, and the other point is (#,0)

to get x-intercept:
y=0:
3x=2 >> x=2/3

to get y-intercept:
x=0:
<span>-6y=2 >>> y = -1/3</span>

5 0

3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

4 years ago

Solve for c: 6/15=2/c

Xelga [282]

6/15 = 2/c
6/3 = 2, therefore you must divide 15 by 3 to get 5. c = 5
6/15 = 2/5

6 0

4 years ago

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