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melisa1 [442]
3 years ago
10

Malcolm and Ravi raced each other.

Mathematics
1 answer:
Semenov [28]3 years ago
3 0

Malcolm maximum speed is 200 km/h and Ravi maximum speed is 320 km/h

Step-by-step explanation:

Lets assume Malcolm maximum speed to be M km/h and Ravi  maximum speed to be R km/h

Average of their maximum speed is; (M+R)/2 =260 km/h

This can be simplified to M+R= 260*2

M+R = 520.......................................(I)

When Malcolm's speed is doubled,

2M=R+80 km/h ----------------------(ii)

The two equations are;

M+R = 520 ------ M=520-R ----(i)

2M=R+80 ---------------------------(ii)

Replacing M with (i) above

2M=R+80

2(520-R) =R+80

1040 -2R =R+80

1040-80 = R+2R

960 = 3R

960/3 =R

320 =R

M+R =520

M=520-320 =200

Malcolm maximum speed is 200 km/h and Ravi maximum speed is 320 km/h

Learn More

Simultaneous equations:brainly.com/question/12919422

Keywords: Average, maximum, speeds, doubled,

#LearnwithBrainly

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If EG = 59, and EF = 8x - 14, while FG = 4x + 1
lyudmila [28]

Answer:

x = 6

Step-by-step explanation:

EG = 59

EF = 8x - 14

FG = 4x + 1

to find the value of x

EF + FG = EG (same line)

8x - 14 + 4x + 1 = 59

12x -13 = 59

12x = 59 + 13

12x = 72

x = 72 ÷ 12

x = 6

You can even cross check for correct answer

EF + FG = EG

instead of x place the x's value we got

8x - 14 + 4x + 1 = 59

8 (6) - 14 + 4 (6) + 1 = 59

48 - 14 + 24 + 1 = 59

34 + 25 = 59

59 = 59

CROSS - CHECKED

4 0
3 years ago
a baker buys 5 lb bag of sugar.she uses one and 1 and two thirds lb to make some muffins and 2 and three fourths lb to make a ca
Ivenika [448]
The baker uses 4 5/12 lb of sugar. She has 7/12 left
7 0
3 years ago
A hospital’s financial reimbursement payor mix indicates 35% of the patients have Medicare and 15% have Medicaid. Of those who h
Damm [24]

Using conditional probability, it is found that there is a 0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.

<h3>What is Conditional Probability?</h3>
  • <em>Conditional probability</em> is the <u>probability of one event happening, considering a previous event</u>. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Patient has Medicare.
  • Event B: Patient has Medicaid.

For the probabilities, we have that:

  • 35% of the patients have Medicare, hence P(A) = 0.35.
  • Of those who have Medicare, there is a 10% chance they also have Medicaid, hence P(B|A) = 0.1.

Then, applying the <em>conditional </em>probability:

P(B|A) = \frac{P(A \cap B)}{P(A)}

0.1 = \frac{P(A \cap B)}{0.35}

P(A \cap B) = 0.35(0.1)

P(A \cap B) = 0.035

0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.

You can learn more about conditional probability at brainly.com/question/14398287

4 0
2 years ago
Jacob rode his bike 5 3/4 miles last week. This week,he rode 4 times as far as he rode last week. How many miles did Jacob ride
Bess [88]

Answer:

Hope this helps

Step-by-step explanation:

1. Make 5 3/4 into an improper fraction. That would be 23/4. 2. Write 4 in a fraction way. That would be 4/1. 3. Now do 23/4 X 4/1. That would be 92/4. 4. Turn it into a mixed number by doing 92 divided by 4. That would be 23. No fraction after 23. Jacob rode his bike 23 miles this week. :)

4 0
3 years ago
Read 2 more answers
g 1.32 Two points on a sphere of radius 3 are given as P1(3,0,30) and P2(3,45,45): (a) Find the position vectors of P1 and P2. (
Rama09 [41]

Answer:

a) P.V  of is OP₁ = [ 1.5i + 0j + 2.6k ],   P.V  of is OP₂ = [ 1.5i + 1.5j + 2.12k ]

b) Vector connecting P₁ to P₂ is [ 0i + 1.5j + 0.48k ]  

c) cylindrical coordinates are (1.5, π/2, 0.48)

Step-by-step explanation:

Given that;

r = 3

P₁ ( 3, 0°, 30° ),   P₂ ( 3, 45°, 45° )

a)

P.V of P₁

x = rcos∅sin∅ = 3(cos0°) ( sin30°) = (3 × 1 × 0.5) = 1.5

y = rsin∅sin∅  = 3(sin0°) (sin30°)   = (3 × 0 × 0.5) = 0

z = rcos∅        = 3(cos30°)             = ( 3 × 0.866)  = 2.6

∴ P.V  of is OP₁ = [ 1.5i + 0j + 2.6k ]

P.V of P₂

x = rcos∅sin∅ = 3(cos45°) ( sin45°) = (3 × 0.7071 × 0.7071) = 1.5

y = rsin∅sin∅  = 3(sin45°) (sin45°)   = (3 × 0.7071 × 0.7071) = 1.5

z = rcos∅        = 3(cos45°)                 = ( 3 × 0.7071)            = 2.12

∴ P.V  of is OP₂ = [ 1.5i + 1.5j + 2.12k ]

b)

Vector connecting P₁ to P₂ is given by

OP₂ - OP₁ = [ 1.5i + 1.5j + 2.12k ] - [ 1.5i + 0j + 2.6k ]

= [ 0i + 1.5j + 0.48k ]  

c)

P₁P₂ → = [ 0i + 1.5j + 0.48k ]  = [ 1.5j + 0.48k ]  

so in a cylindrical coordinate, it should be

r = √(o² + 1.5²) = 1.5

∅ = tan⁻¹[y/π] = π/2

z = 0.48

cylindrical coordinates are (1.5, π/2, 0.48)

5 0
3 years ago
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