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3 years ago

What is the value of h for the parallelogram?

Mathematics

1 answer:

anastassius [24]3 years ago

3 0

Answer:

9.6 units

Step-by-step explanation:

The area of the parallelogram is the product of the base length and distance between parallel sides, either way you figure it.

16 × 6 = area = 10 × h

96 = 10h

h = 96/10 = 9.6 . . . . units

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Find RA, 90: (2,5) given that point A is located at (-3, -3).

Anna71 [15]

Answer:

The value of RA is " 9.43".

Step-by-step explanation:

In the given question there is some typing mistake so, the points are:

R =(2, 5)

A= (-3, -3)

Find:

RA= ? where it is a distance (D).

Formula:

$D= \sqrt{(x_2-x_1)^2+ (y_2-y_1)^2} \\\\\ compare \ the \ value \\\\x_1 = 2\\y_1=5\\x_2=-3\\y_2= -3$

put the value in the formula:

$\Rightarrow D =\sqrt{(-3-2)^2+(-3-5)^2} \\\\\Rightarrow D =\sqrt{(-5)^2+(-8)^2} \\\\\Rightarrow D =\sqrt{25+64} \\\\\Rightarrow D =\sqrt{89} \\\\\Rightarrow D = 9.43\\$

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3 years ago

What is the perimeter of a square

777dan777 [17]

Answer:

4*sides

Step-by-step explanation:

4*sides is the Answer

5 0

3 years ago

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Which line shows the first error in the solution?

Taya2010 [7]

The answer is line 3. Line 3 has -12 - 3 and below that they have -9. It would be
-12 - 3 = -15

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3 years ago

Eliminate the parameter,t, in the parametric equation, x=6cos t, and y =3 sin t

german

X = 6 cos(t)
y = 3 sin(t)

we can rewrite these equations as:

$\frac{x}{6}=cost(t) \\ \\ \frac{y}{3} =sin(t)$

Taking squares of both equations we get:

$( \frac{x}{6})^{2}=sin^{2} (t) \\ \\ 
( \frac{y}{3})^{2}=cos^{2}(t)$

Adding both the equations, we get:

$\frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=sin^{2}(t)+cos^{2}(t) \\ \\ 
 \frac{ x^{2} }{36}+ \frac{ x^{2} }{9}=1$

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3 years ago

Y=3x+8 Y=-2x-2<br>can anyone help me with this ??

vivado [14]

Is it 2 different questions or just one?

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3 years ago

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