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lana66690 [7]
3 years ago
8

How to evaluate 3H +2 for H equals 10

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0

Answer: 32

Step-by-step explanation:

3H+2

3(10)+2

30+2

32

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A solid oblique pyramid has a regular hexagonal base with an area of 54StartRoot 3 EndRoot cm2 and an edge length of 6 cm. Angle
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Answer:

1/4 <u>divided by</u> 1/3

1/3 <u>divided into</u> 1/4

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Write four different expressions for the perimeter of a pentagon whose sides are all s-2 units long?
Masteriza [31]

Hey there!

1. 5(s-2) This is because s-2 is the length of each side, and there are 5 sides in a pentagon all of that length, so multiplying it by 5 like this shows its perimeter.

2. 5s-10 This can be found by distributing the first equation, multiplying both s and -2 by 5.

3. (s-2) + (s-2) + (s-2) + (s-2) + (s-2) Each grouping in the parenthesis represents each of the 5 sides, so adding them all together will get you the perimeter.

4. 5(s) + 5(-2) This one is most like the first one, except it's a little more spread out. Multiply the term s by the 5 sides in one grouping, and the integer -2 by 5 in the other.

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4 0
3 years ago
6= 2(y+2). Helppppppppppppppp
Licemer1 [7]

Answer:

y=1

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4 0
3 years ago
What numbers can give me 8 when added and 30 when multiplied
Paul [167]
In this problem, it is important to take note that the number of numbers to be utilized isn't specified so it can be up to a thousand numbers. It wasn't also specified if repeating of numbers is allowed or not. So with those taken into consideration and the condition presented in mind, the numbers that can give you 8 when added and 30 when multiplied are 2, 3, 5, -1, and another -1. The derivation from this is mainly from factorization and a little bit of logic.

here is the solution.

2 x 3 x 5 x -1 x -1 = 30
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30 = 30

2 + 3 + 5 + -1 + -1 = 8
5 + 5 + -1 + -1 = 8
10 + -1 + -1 = 8
9 + -1 = 8
8 = 8
7 0
3 years ago
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