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makkiz [27]
3 years ago
13

5 is what percentage of 8?

Mathematics
1 answer:
andriy [413]3 years ago
6 0
5/8 = .625 which means that 5 is 62.5% of 8
4/7 = .571 which means that 4 is 57.1% of 7

hope this helps(;
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One year there was a total of 59 commercial and noncommercial orbital launches worldwide. In addition, the number of noncommerci
Lina20 [59]

Answer:

The number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40.

Step-by-step explanation:

IMPORTANT INFORMATION: The number of noncommercial orbital launches was two more than twice the number of commercial orbital launches.

Let's say that the number of commercial orbital launches is equal to x. Now, the number of noncommercial orbital launches is equal to 2x+2.

We are told that if we add the number of commercial and noncommercial orbital launches together we will get 59.

Therefore, if we add 2x+2 with x we should get 59:

2x+2+x=59

3x+2=59

3x=57

x=19

This is how we can come to the answer that the number of commercial orbital launches is equal to 19 and the number of noncommercial orbital launches is equal to 40 (2x+2=2*19+2=38+2=40).

Hope this helps!

4 0
3 years ago
Find the perimeter of the triangle whose vertices are the following, specified points in the plane.
hichkok12 [17]

Given:

The vertices of the triangle are (-10,-3), (1,4) and (-1,7).

To find:

The perimeter of the triangle.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let the vertices of the triangle are A(-10,-3), B(1,4) and C(-1,7).

Using distance formula, we get

AB=\sqrt{(1-(-10))^2+(4-(-3))^2}

AB=\sqrt{(1+10)^2+(4+3)^2}

AB=\sqrt{(11)^2+(7)^2}

AB=\sqrt{121+49}

AB=\sqrt{170}

Similarly,

BC=\sqrt{\left(-1-1\right)^2+\left(7-4\right)^2}=\sqrt{13}

AC=\sqrt{\left(-1-\left(-10\right)\right)^2+\left(7-\left(-3\right)\right)^2} =\sqrt{181}

Now, the perimeter of the triangle is

Perimeter=AB+BC+AC

Perimeter=\sqrt{170}+\sqrt{13}+\sqrt{181}

Perimeter\approx 13.038+3.606+13.454

Perimeter=30.098

Therefore, the perimeter of the triangle is 30.098 units.

8 0
3 years ago
Can someone pls HELP me
zhenek [66]

Answer:

65 degrees

Step-by-step explanation:

7 0
3 years ago
Riya is applying mulch to her garden. She applies it at a rate of 250,000 cm^3 for every m^2 of garden space
Fudgin [204]
Rate is the change in one variable in relation to another variable. Generally, rate is calculated as follows:

R = ΔV1/ΔV2

Where
R = Rate
ΔV1 = Change in variable 1
ΔV2 = Change in variable 2

In the current scenario,
ΔV1 = 250,000 m^3 of mulch applied
ΔV2 = 1 m^2 of garden space

Therefore,
Rate of applying much is, R = 250,000/1 = 250,000 m^3/m^2
8 0
3 years ago
Read 2 more answers
Identify the measure of arc HD◠. HELP ASAP!!
horsena [70]

In the triangle, the remaining angle has measure (180-92-38)^\circ=50^\circ. Then by the intersecting secants theorem,

50^\circ=\dfrac{102^\circ-m\widehat{HD}}2\implies\boxed{m\widehat{HD}=2^\circ}

(assuming 102º refers to the measure of arc PK)

8 0
3 years ago
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