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Ulleksa [173]
3 years ago
5

Jane runs 6 miles in 44 minutes. At the same rate, how many minutes would she take to run 9 miles?

Mathematics
1 answer:
polet [3.4K]3 years ago
8 0

Answer:

66 minutes

Step-by-step explanation:

<u>Solve for speed</u>

speed = distance / time

speed = 6 / 44

<u>Substitute in speed to second equation and solve for time</u>

distance / speed = time

9 / (6/44) = time

66 = time taken

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the cylinder has radius 4√3 and hight h. the total surface area of the cylinder is 56π√6. find the exact value of h giving the a
Arte-miy333 [17]

The area of the cylinder is a function of its height (h) and radius, (\mathbf{4\sqrt 3})

The exact value of h is: \mathbf{7\sqrt 2- 4\sqrt 3}

The given parameters are:

\mathbf{Area =56\pi\sqrt 6}

\mathbf{r=4\sqrt 3}

The surface area of a cylinder is calculated as:

\mathbf{Area = 2\pi rh + 2\pi r^2}

Substitute values for Area

\mathbf{56\pi\sqrt 6= 2\pi rh + 2\pi r^2}

Divide through by pi

\mathbf{56\sqrt 6= 2 rh + 2r^2}

Substitute value for r

\mathbf{56\sqrt 6= 2 (4\sqrt 3)h + 2(4\sqrt 3)^2}

\mathbf{56\sqrt 6= 8h\sqrt 3 + 2\times 48}

\mathbf{56\sqrt 6= 8h\sqrt 3 + 96}

Collect like terms

\mathbf{8h\sqrt 3 = 56\sqrt 6- 96}

Make h the subject

\mathbf{h = \frac{56\sqrt 6}{8\sqrt 3}- \frac{96}{8\sqrt 3}}

\mathbf{h = 7\sqrt 2- \frac{12}{\sqrt 3}}

Rationalize

\mathbf{h = 7\sqrt 2- \frac{12\sqrt 3}{3}}

\mathbf{h = 7\sqrt 2- 4\sqrt 3}

Hence, the exact value of h is: \mathbf{7\sqrt 2- 4\sqrt 3}

Read more about surface areas t:

brainly.com/question/25131428

5 0
2 years ago
10.00 for movie tickets ​
IgorLugansk [536]

Answer:

Yup!

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Math help! Is this correct? If not what’s the real answer
miv72 [106K]

Answer:

It's correct

Step-by-step explanation:

Good job! arcsin(0.9659) is indeed 75 degrees

3 0
3 years ago
Which point is not on the graph of the equation y=10+x
RSB [31]

Answer:

C. (8, 2)

Step-by-step explanation:

To find which point is not on the graph, find which set of coordinates makes the equation incorrect.

When plugged into the equation, the point (8, 2) makes it incorrect:

y = 10 + x

2 = 10 + 8

2 = 18

2 \neq 18

The equation is incorrect because 2 is not equal to 18.

So, the point that is not on the graph is C. (8, 2)

6 0
2 years ago
A track-and-field athlete releases a javelin. The height of the javelin as a function of time is shown on the graph below. Use t
Georgia [21]
Part 1:
 
 For this case we must see in the graph the axis of symmetry of the given parabola.
 We have then that the axis of symmetry is the vertical line t = 2.
 Answer:
 
The height of the javelin above the ground is symmetric about the line t = 2 seconds:

 
Part 2:

 
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
 We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
 Then, we must observe the moment when it returns to be 20 feet above the ground.
 For this, observing the graph we see that:
 h (3) = 20 feet
 Therefore, a height of 20 feet is again reached in 3 seconds.
 Answer:
 
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
5 0
3 years ago
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