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3 years ago

7

PLS HELP!! ASAPPPPPPPP

1 answer:

morpeh [17]3 years ago

5 0

Keep the denominator

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How much does Greg earn per hour? Explain how to determine the unit rate from the table?

Butoxors [25]

Answer:

Well you can already answer that(37)

Step-by-step explanation:

In 3 hours and 30 minutes Greg has earned 64.75 dollars if you take that amount(the amount earned in 3 and a half hours) and divide it by the 3 1/2 hours(the time it took to earn that amount) you get 18.50 which is the amount you earn per half hour since that graph is increasing at 30min. per 18.50 or the amount.

3 0

4 years ago

JK is tangent to OG at point K, m2JKG = (x+¹3¹), and m2KGJ = (x+2). What is<br><br> mzJGK=

brilliants [131]

Ok ok fine here is the answer

3 0

3 years ago

Express 100,000 as a power of 10

Vedmedyk [2.9K]

Answer:

10^5

Step-by-step explanation:
10 multiplied by itself five times (10*10*10*10*10) is 100,000.

7 0

2 years ago

1 7/8 divided by 2 8/11

Bingel [31]

Answer: 11/16

<u>Turn 1 7/8 into an Improper Fraction</u>

Multiply 1×8 and get 8. Now add 7 and get 15.

1 7/8 = 15/8

<u>Turn 2 8/11 into an Improper Fraction</u>

Multiply 2×11 and get 22. Now add 8 and get 30.

2 8/11 = 30/11

<u>Do Keep Change Flip</u>

Keep: 15/8

Change ÷ into ×

Flip: 30/11 into 11/30

Your New Problem: 15/8×11/30

<u>Multiply</u>

15/8×11/30=165/240

<u>Simplify</u>

165/240÷15/15=11/16

3 0

4 years ago

Read 2 more answers

You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio

nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that $\sigma = 12000$

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1000 = 1.96\frac{12000}{\sqrt{n}}$

$1000\sqrt{n} = 1.96*12$

Dividing both sides by 1000:

$\sqrt{n} = 1.96*12$

$(\sqrt{n})^2 = (1.96*12)^2$

$n = 553.2$

Rounding up:

A sample size of 554 is needed.

5 0

3 years ago