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gladu [14]
3 years ago
15

Kazimir stopped jogging at 8:15. He started jogging 20 minutes earlier. At what time did Kazimir start jogging?

Mathematics
2 answers:
earnstyle [38]3 years ago
6 0

7:55

That he answer

EleoNora [17]3 years ago
6 0

Answer:

7:55

Step-by-step explanation:

8:15 - 20

8:05 (10 minutes)

7:55 (20 minutes)

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R-(-4x - (y + y)); use x = -4, and y = -3 evaluate ​
Romashka-Z-Leto [24]

Answer:

insert values of x and y

r - ( -4(-4) - ( -3-3))

r - ( 16 +6 )

r - 22

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8 0
3 years ago
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tankabanditka [31]

Answer:

God bless you all and always

6 0
2 years ago
Please help! Greatly appreciated sorry for really bad quality
Degger [83]
The first answer.

Point P is at (50,-40) the distance from Q to P is 80 units which you can find by subtracting the x of Q (-30) from the x of P (50).
50-(-30)=80
It then tells you point R is vertically above point Q so you know your x value for R will be the same as Q.
Add your distance from Q to P of 80 units to the y value of Q because you are traveling up.
-40+80=40
R will have a point of (-30,40) and a distance of 80 units
7 0
3 years ago
How many eight notes is equal to a halfnote ​
Dominik [7]

Answer: Four eighth notes

Sixteenth Notes

Step-by-step explanation: Two quarter notes equal one half note in duration and four quarter notes equal one whole note. Two eighth notes equal one quater note in duration. Four eighth notes equal one half note in duration and eight eighth notes equal one whole note.

6 0
3 years ago
Read 2 more answers
A batch of 40 semiconductor chips is inspected by choosing a sample of 5 chips. Assume 10 of the chips do not conform to custome
butalik [34]

Answer:

a) 658008 samples

b) 274050 samples

c) 515502 samples

Step-by-step explanation:

a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.

So, the number of samples = ⁴⁰C₅ = 658008 samples

b) How many samples of 5 contain exactly one nonconforming chip?

There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways

¹⁰C₁ = 10 ways

then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways

³⁰C₄ = 27405 ways

So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples

c) How many samples of 5 contain at least one nonconforming chip?

The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)

Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples

Total number of samples = 658008

The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples

6 0
3 years ago
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