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asambeis [7]
3 years ago
15

23 points to whoever can answer this question !!

Mathematics
1 answer:
Tamiku [17]3 years ago
3 0

-2 2/5

as an improper fraction

-(5*2 +2)/5 -12/5

-12 divided by 5


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i need it too

Step-by-step explanation:

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You are saving for a pair of shoes. After saving for 5 weeks you have $42.50 saved. If you save the amount each week how much wi
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you take the amount you have and divide it with 14 week (I think)

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The matrix A = −14 −6 6 28 12 −4 0 0 4 has characteristic polynomial
rosijanka [135]

Answer:

Characteristic equation:

p(\lambda) = -\lambda^3 + 2\lambda^2 + 8\lambda

Eigen values:

\lambda_1 = 0, \lambda_2 = -2, \lambda_3= 4

Step-by-step explanation:

We are given the matrix:

\displaystyle\left[\begin{array}{ccc}-14&-6&6\\28&12&-4\\0&0&4\end{array}\right]

The characteristic equation can be calculated as:

det(A-\lambda I) = 0\\|A-\lambda I| = 0

We follow the following steps to calculate characteristic equation:

=det\Bigg(\displaystyle\left[\begin{array}{ccc}-14&-6&6\\28&12&-4\\0&0&4\end{array}\right]-\lambda\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]\Bigg)\\\\= det\Bigg(\displaystyle\left[\begin{array}{ccc}-14-\lambda&-6&6\\28&12-\lambda&-4\\0&0&4-\lambda\end{array}\right]\Bigg)\\\\=(-14-\lambda)[(12-\lambda)(4-\lambda)]+6[28(4-\lambda)]-6[(28)(0)-(12-\lambda)(0)]\\\\= -\lambda^3 + 2\lambda^2 + 8\lambda

p(\lambda)= -\lambda^3 + 2\lambda^2 + 8\lambda

To obtain the eigen values, we equate the characteristic equation to 0:

p(\lambda) = -\lambda^3 + 2\lambda^2 + 8\lambda = 0\\-\lambda(\lambda^2-2\lambda-8) = 0\\-\lambda(\lambda^2-4\lambda+2\lambda-8) = 0\\-\lambda[(\lambda(\lambda-4)+2(\lambda-4)] = 0\\-\lambda(\lambda+2)(\lambda-4) = 0 \\\lambda_1 = 0, \lambda_2 = -2, \lambda_3= 4

We can arrange the eigen values as:

\lambda_1 = 0, \lambda_2 = -2, \lambda_3= 4\\-2 < 0 < 4\\\lambda_2 < \lambda_1 < \lambda_3

3 0
3 years ago
Please help! 70 points :)<br> Will award brainliest
dexar [7]

Answer:

38 = FH

Step-by-step explanation:

Because this is a rectangle, IG = FH

We know that IE + EG = FH

We also know that IE = EG   (perpendicular bisectors)

IE = EG

3x+4 = 5x-6

Subtract 3x from each side

3x-3x+4 = 5x-3x-6

4 = 2x-6

Add 6 to each side

4+6 =2x

10 =2x

Divide by 2

10/2 =2x/2

5=x


Now lets find FH

IE + EG = FH

3x+4 + 5x-6  = FH

Combine like terms

8x-2 = FH

Substitute in x =5

8*5-2

40-2

38 = FH

7 0
3 years ago
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Find x:<br> Angle 2x<br> Angle 3x-20<br> For geometry
krok68 [10]
Answer: x=40
(Extra letters)
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