1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
abruzzese [7]
2 years ago
12

A teacher gives a 20 point quiz 210 students the scores are listed below what percentile corresponds to the score of 45

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
4 0
Yo sjdjsndnd dos dpsss
You might be interested in
Multiply and simplify: (6x + 3y)(6x − 3y)
nasty-shy [4]

Answer:

36x² - 9y²

Step-by-step explanation:

We see that the given expression (6x + 3y)(6x - 3y) looks just like the expression (a + b)(a - b). When multiplied out, this is a difference of squares identity that I highly recommend you memorise:

(a + b)(a - b) = a² - b²

Here, a = 6x and b = 3y, so plug these in:

(6x + 3y)(6x - 3y) = (6x)² - (3y)² = 36x² - 9y²

5 0
3 years ago
Read 2 more answers
What is the product of any integer and -1
mixas84 [53]

Answer:

The negative counterpart

Step-by-step explanation:

x * -1 = -x

For example, 3 * -1 = -3

Hope this helps.

5 0
3 years ago
Read 2 more answers
Jacob Is Twice as old as Sue. The sum of their ages is 69 years. How old is Jacob?
NemiM [27]
x-Sue\\2x-Jacob\\\\x+2x=69\\\\3x=69\ \ /:3\\\\x=69:3\\\\x=23-Sue\\\\2x=2\cdot23=46-Jacob\\\\Answer:Jacob\ is\ 46.
7 0
3 years ago
What is the answer to -6(a+8)
Dafna11 [192]

Answer: -6a-48

Step-by-step explanation:

First -6 goes into a and that turns into -6a and then -6 goes into 8 and that turns into -48 so ur answer would  be: -6a-48

ur welcome

8 0
3 years ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
Other questions:
  • A teacher wanted to buy a chair, a bookshelf, two tables and a desk. She spent $900 for all five items and the chair and the des
    5·1 answer
  • Which is the graph of f(x)=sqrt x?
    12·1 answer
  • Jay is measuring the sides and angles of a number of triangles looking for a triangle that is congruent to triangle XYZ below.
    15·2 answers
  • If the points below represent a direct variation, find the missing value (5,14)and (x,28)
    7·1 answer
  • An ice cream shop sold 48 vanilla milkshakes in a day , which was 40% of the total number of milkshakes sold that day. What was
    10·1 answer
  • Select the two values of x that are roots of this equation
    9·1 answer
  • Solve the equation. X^2 + 22x = -40<br> The solutions to the equation are
    5·1 answer
  • Solve 2(x + 3) = x-4
    11·1 answer
  • Solve for x and y<br><br> x-y=11<br><br> 2x+y=19
    9·2 answers
  • Solve the equation showing all work.<br><br> 3x²+5=152
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!